Answer:
-In the isothermal process, temperature is kept constant so change in temperature when work is done on the system is zero. The internal energy of the system depends on temperature. So, $\Delta U=0$.
Explanation:
Answer:
constant horizontal force developed in the coupling C = 11.25KN
the friction force developed between the tires of the truck and the road during this time is 33.75KN
Explanation:
See attached file
Answer:
I started answering this before everything was erases, but briefly
W = 1/2 K x^2 so K = 2 W / x^2 = 6 * 25 = 150
Also F = - K X = 150 * 1/5 = 30 N at max extension
m = F / a = 30 /15 = 2 kg
Since max extension occurs at t = 0 you can write
x = A sin ω t
v = ω A cos ω t
a = -ω^2 A sin ω t note that there is no phase angle here
Also at .1 compression
.1 = .2 sin ω t and sin ω t = 1/2 and ω t = 30 deg = pi / 6
Substiture these values above to get velocity and acceleration when
ω t = 30 deg
Air pressure decreases with altitude
hope that helps you!
The answer for this problem is clarified through this, the
system is absorbing (+). And now see that it uses that the SURROUNDINGS are
doing 84 KJ of work. Any time a system is overshadowing work done on it by the
surroundings the sign will be +. So it's just 12.4 KJ + 4.2 = 16.6 KJ.