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podryga [215]
3 years ago
10

Suppose the moon rotated on its axis just as quickly as Earth. Would we still always see the same side of the moon from Earth?

Physics
1 answer:
jasenka [17]3 years ago
3 0

Answer:

No, The Moon, on the other hand, rotates once around its every 28 days, and once around the Earth in that same 28 days. The result of this combination is that the same side of the Moon is always facing the Earth.

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What was the purpose of the little Albert experiment?
Murljashka [212]

Answer:

to condition a phobia in an emotionally stable child

3 0
3 years ago
A 1.2 kg basketball is thrown upwards. What is the potential energy of the basketball at the top of its path if it reaches a hei
Dahasolnce [82]

Answer:

Answer is 183.6 J

Explanation:

Using the Physics reference sheet the formula for Potential energy is

(mass) x (gravity) x (height)

Mass= 1.2

Gravity I used is 9.81 (use 10 to get the answer most schools use)

Height= 15.6

5 0
3 years ago
A satellite is in a circular orbit around the Earth at an altitude of 2.80 3 106 m. Find (a) the period of the orbit, (b) the sp
Katen [24]

Explanation:

Given that,

Altitude h= 2.803\times10^{6}\ m

We need to calculate the radius

r=R+h

Where, R = radius of the earth

h = radius of altitude

Put the value into the formula

r=(6.38\times10^{6}+2.803\times10^{6})

r=9.18\times10^{6}\ m

(a). We need to calculate the period of the orbit,

Using formula of period

T^2=\dfrac{4\pi^2}{GM}r^3

T^2=\dfrac{4\pi^2}{6.67\times10^{-11}\times5.98\times10^{24}}\times(9.18\times10^{6})^3

T^2=76570372.9509\ sec

T=8750.45\ sec

(b). We need to calculate the speed of the satellite

Using formula of speed

v^2=\dfrac{GM}{r}

Put the value into the formula

v^2=\dfrac{6.67\times10^{-11}\times5.98\times10^{24}}{9.18\times10^{6}}

v^2=43449455.3377\ m/s

v=6.59\times10^{3}\ m/s

(c). We need to calculate the acceleration of the satellite

Using formula of acceleration

a_{c}=\dfrac{v^2}{r}

Put the value into the formula

a_{c}=\dfrac{(6.59\times10^{3})^2}{9.18\times10^{6}}

a_{c}=4.73\ m/s^2

Hence, This is the required solution.

6 0
4 years ago
A flat coil of wire has an area A, N turns, and a resistance R. It is situated in a magnetic field, such that the normal to the
Phantasy [73]

Answer:

3.4 x 10^-4 T

Explanation:

A = 1.5 x 10^-3 m^2

N = 50

R = 180 ohm

q = 9.3 x 106-5 c

Let B be the magnetic field.

Initially the normal of coil is parallel to the magnetic field so the magnetic flux is maximum and then it is rotated by 90 degree, it means the normal of the coil makes an angle 90 degree with the magnetic field so the flux is zero .

Let e be the induced emf and i be the induced current

e = rate of change of magnetic flux

e = dФ / dt

i / R = B x A / t

i x t / ( A x R) = B

B = q / ( A x R)

B = (9.3 x 10^-5) / (1.5 x 10^-3 x 180) = 3.4 x 10^-4 T

6 0
3 years ago
What is the speed of light and sound? Which one is faster?
meriva
The speed of light: 299,782,458 m / s
The speed of sound: 340.29 m / s

Light is faster
4 0
3 years ago
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