This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Hope it helps, despite being this long!
2x-7=29
"Seven less than" => minus 7.
"Two times <u>a number</u>" => 2x (x is the unknown number)
"is twenty-nine" => =29
Putting it all together,
-7 + 2x = 29
or
2x-7=29
(if you were wondering x is equal to 18)
Answer:
The range is 2
Step-by-step explanation:
The median is 5. The mode is 5. The mean is 5.
Answer:
x - 0.8y
Step-by-step explanation:
5.20/6.5 = $0.80 per pound
x = total cost of potatoes
y = number of potatoes
x = 0.8y
Answer:
so it's
3/7m<21
and we devide both sides of the inequality.
/2r-1\>7
And we can rewrite it as a compound Inequality
2r-1<7 (or) 2r-1>7 Ima give u the enter
[r<-3 or r>4 I guess it's like this❕
