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user100 [1]
3 years ago
6

Tickets for the karaoke talent show sponsored by the Speech Club were priced at $3 for adults and $2 for students. The club trea

surer counted 300 tickets sold for a total of $650. Write and solve a system of equations to determine how many adult and student tickets were sold.
Mathematics
1 answer:
vfiekz [6]3 years ago
5 0

Answer:

50 adults and 250 students tickets were sold

Step-by-step explanation:

Given data

Let the number of adults be x and students be y

3x+2y=650------1

x+y= 300---------2

from 2

x= 300-y

put the value of x in 1

3(300-y)+2y= 650

900-3y+2y= 650

900-y= 650

900-650= y

y=250

put the value of y in 2

x+250= 300

x= 300-250

x= 50

Hence 50 adults and 250 students tickets were sold

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write an equation of the line containing the specified point and perpendicular to indicated line. (-5,6) 4x-y=3
Radda [10]
<h2>Greetings!</h2>

Answer:

y = \frac{1}{2}x + \frac{29}{4}

Step-by-step explanation:

First, we need to rearrange the equation to make it y = mx + c

4x - y = 3

y + 3 = 4x

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\frac{-1}{gradient}

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Now to find the equation of a line you can use the following equation:

y - y₁ = m(x - x₁)

Where y₁ is the y-coordinate, x₁ is the x-coordinate and m is the gradient. Plug the values in:

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<h2>Hope this helps!</h2>
8 0
3 years ago
A Regional College uses the SAT to admit students to the school. The university notices that a lot of students apply even though
Aliun [14]

Answer:

0.191 is the probability that a group of 12 randomly selected applicants would have a mean SAT score that is greater than 525 but below the current admission standard of 584.

Step-by-step explanation:

We are given the following information in the question:

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Standard Deviation, σ = 100

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We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(greater than 525 but 584)

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0.191 is the probability that a group of 12 randomly selected applicants would have a mean SAT score that is greater than 525 but below the current admission standard of 584.

3 0
3 years ago
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