Ask question

Ask question

All categories

3 years ago

11

Help! I'm not sure how to set this up. Here is the question; Faye paid $16.00 for a pair of shorts that were 20% off. What was t

he original price of the shorts.

2 answers:

IrinaVladis [17]3 years ago

6 0

80/100*n=16

80n=1600

n=1600/80=160/8=20

---------------------------------------

Original price: $20.00

poizon [28]3 years ago

3 0

The original price of the shorts would have been $19.20. To find this answer you would have to multiply and add.
First thing I did was turn 20% into a decimal by moving the decimal to the left 2 times.(.20)
Second thing I did was multiply 16.00*.20. Which came up to be 3.20.
The third thing that you would have to do is add 3.20 to the price Faye paid for the shorts.
3.20+16.00
And the original price would have came up to $19.20
Hope this helps:)

You might be interested in

Find the value of x. Round your answer to the nearest tenth.

NikAS [45]

Answer:

In this question, we can use the Pythagorean theorem to solve for x.

11^2 + x^2 =24^2

x^2 = 24^2 -11^2

x is about 21.3

Let me know if this helps!

8 0

2 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

2 years ago

Which is the graph of the following inequality?

icang [17]

Answer:

D) graph D

Step-by-step explanation:

x² < 4

x < $\sqrt{4}$ which means x < 2 and x > -2

5 0

2 years ago

Yesterdays afternoon temperature was 21 °F. It plunged overnight to -3 °F. How many degrees did the temperature drop?

White raven [17]

Answer:

the answer is b. 18

3 0

2 years ago

Read 2 more answers

Quien me ayuda?porfa ;-;

asambeis [7]

I don't understand your language sorry

3 0

2 years ago