Answer:
(3, -1)
Step-by-step explanation:
4
That problem is equal to (2•2•2•2) -(2•2•2+2•2)
Or
16-(8+4)
6×10
=60
niceeeeeeeeeeee
1
(8^1)^0
We know that a^b^c = a^ (b*c)
8^1 ^0 = 8^(1*0) = 8^0 =
Anything raised to the 0 power is 1
=1
Use the Pythagorean theorem two times:
second time:
