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tangare [24]
2 years ago
8

F(x) = square root 32x g(x) = square root 2x

Mathematics
1 answer:
otez555 [7]2 years ago
5 0

Given:

The two functions are:

f(x)=\sqrt{32x}

g(x)=\sqrt{2x}

To find:

The (f\cdot g)(x). Assume x\geq 0.

Solution:

We have,

f(x)=\sqrt{32x}

g(x)=\sqrt{2x}

Now,

(f\cdot g)(x)=f(x)\cdot g(x)

(f\cdot g)(x)=\sqrt{32x}\cdot \sqrt{2x}

(f\cdot g)(x)=\sqrt{32x\times 2x}

(f\cdot g)(x)=\sqrt{64x^2}

(f\cdot g)(x)=8x

Therefore, the correct option is A.

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5. Solve by using the square root property.<br>(x - 3)² +6=1​
Veseljchak [2.6K]

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Step-by-step explanation:

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        -6   -6

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x = 3 + i±√5

since its ±

two possible answers

x = 3 + i+√5

x = 3 + i-√5

Or

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(x-3)+  √6= √ 1

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Answers

x= 4 - √6

x= 4 +√6

6 0
3 years ago
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