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Harman [31]
3 years ago
8

suppose f(x) is continuous and that f(-5)=2, f(0)=-3. f(3)=2, f(7)=-4, f(8)=-1.Which smallest interval where f (x)= 0 is guarant

eed to have a solution: [-5,0], [0,3], [3,7], or [7,8]?
Mathematics
1 answer:
ella [17]3 years ago
7 0

Answer:

[0,3]

Step-by-step explanation:

Using a special case of mean value theorem, The Intermediate Zero Theorem:

if sign changes in continuous function, it pass through zero:

f(-5)=2, f(0)=-3. f(3)=2, f(7)=-4, f(8)=-1

[-5,0], [0,3], [3,7] guarantee a solution

smallest : [0,3]

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elena-s [515]

This problem can be solved directly by neglecting the initial velocity given. All we have to do is to plug in t = 4 in the given equation. That is:

h = -16^2 + 123 * 4

h = 236 ft

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3 years ago
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2 years ago
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muminat

Answer:

a = 18

Step-by-step explanation:

2(a-7)=a+4

Distribute 2 into left side: 2a -14 = a + 4

subtract a from both sides  2a-a-14 = a+4-a

Simplify: a  - 14 = 4

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If wanted, plug a into original to double check work:

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Using f(x) = 4x + 6 with the domain of {-1,0,2}, find the range
konstantin123 [22]
The range is the output of the function, and there are many ways to find it and write it. Let's find it first by plugging in all the domain values (domain means input) into the function:
f(-1) = 4(-1)+6=-4+6=2
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We have all of our values. We can either write the range as:
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