Answer:
Um i'ma just guess i'm not really good at math even if i'm in honors so i think its D i believe
Step-by-step explanation:
Answer:
A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.
another way is
This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.
So,
(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA
Step-by-step explanation:
bran-list please
7/8 of an hour is 52.5 minutes. 3/10 of 52.5 minutes is 15.75 minutes. They spent 15.75 minutes warming up and cooling down.
Answer:
Step-by-step explanation:
∴Zero power of any number is equal to 1
Answer:
a) To earn C he needs at least 68 and less than 98
b) No, he couldn't make it.
Step-by-step explanation:
I. His avg value is (382 + x)/6
I pick a random number and that gave
(68 => to reach 75) and (98 => to reach 80)
So that makes he needs at least 68 and less than 98
II. The reason why he cannot make it is
if 100 is 100%
= (100 + 382)/6
= 80.33 That's impossible to reach 90
Hope that help :)
