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enyata [817]
2 years ago
8

GAS LAW PROBLEMS:

Chemistry
1 answer:
lesya692 [45]2 years ago
3 0

Answer:

o

Explanation:

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shshdbsussbbzishxbsbbxusbxhzjjxchinga subs sh is znsoa d bea s for the last time you know. tumamamsr rnnfnt I. NJ just bought new house but he got very very very big but just very kind just bought him just now just now but he has his house but he has his house in his house haha hriirnr is Enfield in his head ️ BF do feel free for me quebro Ayer dry do it for you to do feel like fun for ️ do feel like fun fun fun fun for the last time fun for the last time for free from my gf for free from the other side for from a fe has his house haha he has been busy hereditary so we are going through it and don't feel free can go jump yes very big lol that good in my head that ft in a good game from good get good good GG from a great gAA

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A. Apple juice is an example of a homogeneous mixture.

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Manganese nodules are considered a valuable resource from the ocean floor because they are abundant and contain not only mangane
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Answer: iron (oxides of iron)

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3 years ago
Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying
PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (K_a for HF is 6.8\times 10^{-4}.)

[HF] = 0.280 M

Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = K_a=6.8\times 10^{-4}

HF\rightleftharpoons H^++F^-

Initially

c          0            0

At equilibrium :

(c-x)      x             x

The expression of disassociation constant is given as:

K_a=\frac{[H^+][F^-]}{[HF]}

K_a=\frac{x\times x}{(c-x)}

6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}

Solving for x, we get:

x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

[H^+]=x=0.01346 M

The pH of the solution is ;

pH=-\log[H^+]=-\log[0.01346 M]=1.87

The pH of an 0.280 M HF solution is 1.87.

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As you go down group one of the periodic table, the reactions become and more
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vigorous

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As you go down group one of the periodic table, the reactions become and more vigorous.

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