Answer: B
he has 24 in his supply!
Step-by-step explanation:
Area of the bigger rectangle =(18×8)cm
2
=144cm
2
Area of the smaller rectangle =((30−18)×(8−6))=(12×6)cm
2
=72cm
2
∴ Total area = area of smaller rectangle + area of bigger rectangle =(72+144)cm
2
=216cm
2
There isn’t any correct answer
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
The desired answer is probably that
2x + 1 = 67
is the equation that can be used to solve the problem. In this case, x represents the smallest integer.
_____
I like to work problems in consecutive integers by considering their average. Here, it is 67/2 = 33.5. The two consecutive integers whose average is 33.5 are 33 and 34, the solution to the problem. For this, the first equation applies, where x is the value halfway between the two integers. (This answer (2x=67) would likely get marked wrong by your computer grading system.)