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rewona [7]
2 years ago
9

4. What determines which goods a country should produce and export?

Physics
1 answer:
tangare [24]2 years ago
8 0

Answer:

net exporter

Explanation:

You might be interested in
Calculati rezistenta filamentului unui bec al lanternei de buzunar daca la tensiunea de 3,5 v el este parcurs de un curent cu in
Gennadij [26K]

Answer:

Resistencia = 12.5 Ohmios

Explanation:

Dados los siguientes parámetros;

Voltaje = 3.5 Volts

Corriente = 0.28 Amps

Para encontrar el resistencia;

La ley de Ohm establece que a temperatura constante, la corriente que fluye en un circuito eléctrico es directamente proporcional al voltaje aplicado en los dos puntos e inversamente proporcional a la resistencia en el circuito eléctrico.

Matemáticamente, La ley de Ohm viene dada por la fórmula;

Voltaje = corriente * resistencia

Resistencia = voltaje/corriente

Resistencia = 3.5/0.28

Resistencia = 12.5 Ohmios

Por tanto, la resistencia del filamento de una linterna de bolsillo es de 12,5 ohmios.

3 0
2 years ago
Determine the frequency of a sound wave if it has a speed of 350 m/s and a wavelength of 3.80 m.
Eva8 [605]
Since we have , v=f×lambda (wavelength). Where v equals 350m/s and wavelength equals 3.80. so it will become f = v/lambda=350/3.80=92.1052Hz
7 0
3 years ago
A jogger runs by a river with a velocity of 7 m s relative to the ground. A leaf floating on the river moves with a velocity of
Hunter-Best [27]

Answer:

The velocity of the leaf relative to the jogger is 5 m/s.                    

Explanation:

Given that,

Velocity of jogger wrt to the ground, V_j=7\ m/s

velocity of leaf wrt the ground, v_i=2\ m/s

We need to find the velocity of the leaf relative to the jogger. Let it is equal to V. So, it is given by :

V=v_j-v_i\\\\V=7-2\\\\V=5\ m/s

So, the velocity of the leaf relative to the jogger is 5 m/s. Hence, this is the required solution.

3 0
3 years ago
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor
const2013 [10]

Complete Question

An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.

Answer:

The torque is  \tau = 34.3 \  N\cdot m

Explanation:

From the question we are told that

   The mass of the steel ball is  m  =  3.0 \  kg

    The length of arm is  l =  70 \ cm  = 0.7 \  m

    The mass of the arm is m_a  = 4.0 \  kg

Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

       r = \frac{l}{2}

=>    r = \frac{ 0.7}{2}  

=>    r = 0.35 \ m  

Generally the magnitude of torque about the athlete shoulder is mathematically represented as

      \tau =  m_a * g * r  + m * g *  L

=>    \tau =  4 * 9.8 * 0.35 + 3 * 9.8 *  0.70

=>    \tau = 34.3 \  N\cdot m

5 0
2 years ago
HELP!!
raketka [301]
Hello!

Since the two weights are <em>off</em> the table, the block will move towards letter F. 

I hope this helps :))
5 0
3 years ago
Read 2 more answers
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