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3 years ago

Which two conditions must exist in order for radiation to occur?

Physics

2 answers:

Ostrovityanka [42]3 years ago

6 0

Answer:

Explanation:

Olenka [21]3 years ago

4 0

a temperature difference and the presence of electromagnetic waves

Explanation:

For radiations to occur, there must be presence of temperature difference and electromagnetic waves.

Radiation is a form of heat transfer that does not require a medium. Any hot body emits radiation from its surface.

A hot body is not at thermal equilibrium with its environment.

It has some of its electrons in excited state and by so they emit radiations.

Electromagnetic waves that vibrates transversely emits radiations. This is the mode of heat transfer in place for most electromagnetic waves

learn more:

Electromagnetic radiation brainly.com/question/6818046

#learnwithBrainly

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Newton’s first law describes the tendency calles

beks73 [17]

The first law is about force or push and pull

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3 years ago

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When its 75 kW (100 hp) engine is generating full power, a small single-engine airplane with mass 700 kg gains altitude at a rat

kobusy [5.1K]

Answer:

0.2289

Explanation:

Power required to climb= Fv where F is force and v is soeed. We know that F= mg hence Power, P= mgv and substituting 700 kg for m, 9.81 for g and 2.5 m/s for v then

P= 700*9.81*2.5=17167.5 W= 17.1675 kW

To express it as a fraction of 75 kw then 17.1675/75=0.2289 or 22.89%

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3 years ago

HELP ME HOW ARE BLACK HOLES FROMED

V125BC [204]

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Stellar black holes form when the center of a very massive star collapses in upon itself.

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3 years ago

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A cart loaded with bricks has a total mass of 22.2 kg and is pulled at constant speed by a rope. The rope is inclined at 27.5 ◦

musickatia [10]

Answer:

W = 1.432 KJ

Explanation:

given,

mass = 22.2 Kg

angle of the rope = 27.5°

distance on the ground = 24 m

kinetic friction= μ = 0.32

acceleration due to gravity, g = 9.8 m/s²

Work done = ?

W = F d cosθ

a = 0 because it is moving with constant speed

equating all the forces acting in x direction

F cosθ = F friction = μN

equating all the forces acting in y direction

F sinθ + N -mg =0

now,

N = mg - F sinθ

putting value of N

F cosθ = μ mg -μ F sinθ

F (cosθ + μsinθ ) = μ mg

$F = \dfrac{\mu mg}{cos\theta + \mu sin\theta}$

$F = \dfrac{0.32 \times 22.2 \times 9.8}{cos 27.5^0+0.32 \times sin27.5^0}$

F =67.28 N

now,

W=F d cosθ

W =67.28 x 24 x cos(27.5)

W =1432.27 J

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7 0

3 years ago

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M/s

SashulF [63]

Answer:

a. Final velocity, V = 2.179 m/s.

b. Final velocity, V = 7.071 m/s.

Explanation:

Given the following data;

Acceleration = 0.500m/s²

a. To find the velocity of the boat after it has traveled 4.75 m

Since it started from rest, initial velocity is equal to 0m/s.

Now, we would use the third equation of motion to find the final velocity.

$V^{2} = U^{2} + 2aS$

Where;

V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
S represents the displacement measured in meters.

Substituting into the equation, we have;

$V^{2} = 0^{2} + 2*0.500*4.75$

$V^{2} = 4.75$

Taking the square root, we have;

$V^{2} = \sqrt {4.75}$

Final velocity, V = 2.179 m/s.

b. To find the velocity if the boat has traveled 50 m.

$V^{2} = 0^{2} + 2*0.500*50$

$V^{2} = 50$

Taking the square root, we have;

$V^{2} = \sqrt {50}$

Final velocity, V = 7.071 m/s.

8 0

3 years ago