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lyudmila [28]
3 years ago
6

To make ice, a freezer that is a reverse Carnot engine extracts 37 kJ as heat at -17°C during each cycle, with coefficient of pe

rformance 5.8. The room temperature is 26.9°C. How much (a) energy per cycle is delivered as heat to the room and (b) work per cycle is required to run the freezer?
Physics
1 answer:
Dvinal [7]3 years ago
5 0

Answer:

a) 6.4 kJ

b) 43.4 kJ

Explanation:

a)

Q_{a} = Heat absorbed = 37 kJ

β  = Coefficient of performance = 5.8

W = Work done

Heat absorbed is given as

Q_{a} = β W

37 = (5.8) W

W = 6.4 kJ

b)

Q  = work per cycle required

Q  = Q_{a} + W

Q  = 37 + 6.4

Q  = 43.4 kJ

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