Question

-2x^3(3x^2-4x+7) ?????

Answer 1

Its -2^3*(-5^2x+7) and 5^3x-14^3

Answer 2

Answer:

$-6x^5+8x^4-14x^3$

Step-by-step explanation:

$-2x^3(3x^2-4x+7)$   Use distributive property

$-2x^3$ · $3x^2$ = $-6x^5$      

$-2x^3$ · $-4x$ = $8x^4$       Product becomes positive because of two negatives

$-2x^3$ · $7$ = $-14x^3$

Group all of those numbers together (in order)

$-6x^5+8x^4-14x^3$