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Scilla [17]
3 years ago
14

How can you represent 100 as an exponential expression with 10 as the base

Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0

Given:

The number of 100.

To find:

The given number as an exponential expression with 10 as the base.

Solution:

We have,

Given number = 100

It can be written as

100=10\times 10

100=10^{1+1}                   [\because a^m\cdot a^n=a^{m+n}]

100=10^2

Here, base is 10 and exponent is 2.

Therefore, the given number can be written as 10^2.

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The polygons are similar solve for x
Gnom [1K]

Answer:

x=12

Step-by-step explanation:

14/21=16/(x+12)

cross multiply

14(x+12)=16(21)

14x+168=336

14x=336-168

14x=168

x=12 (so the side would be x+12=24)

You could also see that 14 is 2/3 of 21, so 16 has to be 2/3 of x+12.  That means x+12 would have to equal 24.  If you take the 12 away from 24, x=12.

6 0
3 years ago
L={l,m,n,o}J={i,j,k,l,m}
guapka [62]

Answer:

L ∪ J = {i, j, k, l, m, n, o}

Step-by-step explanation:

L = {l, m, n, o}   J = {i, j, k, l, m}

The union of two sets is a set that contains every element of either set.

L ∪ J = {i, j, k, l, m, n, o}

4 0
3 years ago
Read 2 more answers
Section 5.2 Problem 6:<br><br>Find the general solution<br><img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2
mihalych1998 [28]

Answer:

y=e^{-3t}(A\: cos\: t+B\:sin\:t)

Step-by-step explanation:

<u>Given Second-Order Homogenous Differential Equation</u>

y''+6y'+10y=0

<u>Use Auxiliary Equation</u>

<u />m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i

<u>General Solution</u>

<u />y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)

Note that the DE has two distinct complex solutions p\pm qi where A and B are arbitrary constants.

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2 years ago
PLEASE HURRY I NEED IT NOW THANK YOU
faltersainse [42]
<span><span /></span>A. using a calculator help a lot you know 








8 0
4 years ago
Write 4/5x3/8 in lowest term
Luden [163]

\frac{12}{40}
this equals = 3 4/40 =☆ 3 1/10☆
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3 years ago
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