HELP ME!!!!!!!!!! the problem is on the picture.

Please help me so lost

Alex777 [14]

Answer:

The answer is the first one - 8 square roots of 3

Step-by-step explanation:

Using formula is sufficient here.

In hexagon there are 6 same triangles.

You calculate the area of one of them by formula (1/2)*(2)*(4square root of 3/3)

You multiply that by 6 and simplify.

The answer is the first one - 8 square roots of 3

I hope I helped you and I will be happy If you mark my answer as brainliest.

6 0

3 years ago

A triangle with coordinates A(1, 1), B(4, 2), C(3, 5) is translated three units down and five units to the left. What are the co

kompoz [17]

Answer:

$A' = (-4,-2)\\B'=(-1,-1)\\C'=(-2, 2)$

Step-by-step explanation:

Given:

$A = (1,1)\\B=(4,2)\\C=(3,5)$

A translation upward or downward affects the $y$ value of a coordinate while a translation left or right affects the $x$ value of a coordinate.

We are translating the whole triangle down three units, so we subtract all the $y$ values by 3.

We are also translating the whole triangle to left left five units, so we will subtract all the $x$ values by 5.

$A = (1-5,1-3)\\B=(4-5,2-3)\\C=(3-5,5-3)$

New Coordinates:

$A' = (-4,-2)\\B'=(-1,-1)\\C'=(-2, 2)$

4 0

3 years ago

Read 2 more answers

Find the vertices and foci of the hyperbola with equation quantity x minus five squared divided by eighty one minus the quantity

Papessa [141]

If you notice, the positive fraction, is the one with the "x" variable in it, that simply means, the hyperbola is opening over the x-axis, so is a horizontal one, therefore

$\bf \textit{hyperbolas, horizontal traverse axis }
\\\\
\cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h\pm a, k)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}
\end{cases}\\\\
-------------------------------$

$\bf \cfrac{(x-5)^2}{81}-\cfrac{(y-1)^2}{144}=1\implies \cfrac{(x-5)^2}{9^2}-\cfrac{(y-1)^2}{12^2}=1~~
\begin{cases}
a=9\\
b=12
\end{cases}
\\\\\\
c=\sqrt{9^2+12^2}\implies c=15\\\\
-------------------------------\\\\
vertices~~(5\pm 9,1)\implies 
\begin{cases}
(14,1)\\
(-4,1)
\end{cases}~~foci~~(5\pm 15,1)\implies 
\begin{cases}
(20,1)\\
(-10,1)
\end{cases}$

3 0

3 years ago

Can someone please help me with this attachment below

Marizza181 [45]

The first one might be cannot be determined
2- rational
3- irrational

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=n%20%2B%207%20%3D%2013" id="TexFormula1" title="n + 7 = 13" alt="n + 7 = 13" align="absmiddle"

torisob [31]

$n+7=13$