Answer:
both will be at liquid state. the particles will move rapidly in all directions and will collide with other particles in random motion
6,02·10²³ --- 1 mol
X -------------- 6,5 mol
X = 6,02·10²³×6,5
X = 39,13·10²³ molecules of Cl₂
Answer : The correct option is, (b) ![1.3\times 10^{-3}M](https://tex.z-dn.net/?f=1.3%5Ctimes%2010%5E%7B-3%7DM)
Explanation :
According to the Henry's law:
![C_{O_2}=k_H\times p_{O_2}](https://tex.z-dn.net/?f=C_%7BO_2%7D%3Dk_H%5Ctimes%20p_%7BO_2%7D)
where,
= molar concentration of
= ?
= partial pressure of
= 1.0 atm
= Henry's law constant = ![1.3\times 10^{-3}mole/L.atm](https://tex.z-dn.net/?f=1.3%5Ctimes%2010%5E%7B-3%7Dmole%2FL.atm)
Now put all the given values in the above formula, we get:
![C_{O_2}=(1.3\times 10^{-3}mole/L.atm)\times (1.0atm)](https://tex.z-dn.net/?f=C_%7BO_2%7D%3D%281.3%5Ctimes%2010%5E%7B-3%7Dmole%2FL.atm%29%5Ctimes%20%281.0atm%29)
![C_{O_2}=1.3\times 10^{-3}mole/L=1.3\times 10^{-3}M](https://tex.z-dn.net/?f=C_%7BO_2%7D%3D1.3%5Ctimes%2010%5E%7B-3%7Dmole%2FL%3D1.3%5Ctimes%2010%5E%7B-3%7DM)
Therefore, the molar concentration of oxygen in water is, ![1.3\times 10^{-3}M](https://tex.z-dn.net/?f=1.3%5Ctimes%2010%5E%7B-3%7DM)