Take -920/360 = -2.55555
Take the fraction part -0.5555555 * 360 = -200
The positive of that would be 160 degrees
Answer:
The original length was 41 inches and the original width was 16 inches
Step-by-step explanation:
Let
x ----> the original length of the piece of metal
y ----> the original width of the piece of metal
we know that
When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box
The dimensions of the box are

The volume of the box is equal to


so

simplify
-----> equation A
Remember that
The piece of metal is 25 in longer than it is wide
so
----> equation B
substitute equation B in equation A

solve for y

Solve the quadratic equation by graphing
using a graphing tool
The solution is y=16
see the attached figure
Find the value of x

therefore
The original length was 41 inches and the original width was 16 inches
Answer:
10
Step-by-step explanation:
one interior angle in a pentagon is 108^o.
5 interior angles are 540^o.
If we add 12+7+16+9+10, we get 54x=540^o
That means x=10
We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!
We are given with ;
Take LCM on both sides :
<em>Multiplying</em> both sides by <em>10</em> ;

Can be <em>further written</em> as ;
Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>


X² + 3x = 10
Convert to standard form.
x² + 3x - 10 = 0
factor x² = x * x
factor -10 = 5 * -2
(x + 5) (x - 2) = 0
x(x -2) + 5(x-2) = 0
x² - 2x + 5x - 10 = 0
x² + 3x - 10 = 0
x + 5 = 0 x² + 3x = 10
x = -5 -5² + 3(-5) = 10
25 - 15 = 10
10 = 10
x - 2 = 0 x² + 3x = 10
x = 2 2² + 3(2) = 10
4 + 6 = 10
10 = 10