Answer:
1.99 M
Explanation:
The molar mass of sodium thiosulfate (solute) is 158.11 g/mol. The moles corresponding to 110 grams are:
110 g × (1 mol/158.11 g) = 0.696 mol
The volume of solution is 350 mL = 0.350 L.
The molarity of sodium thiosulfate is:
M = moles of solute / liters of solution
M = 0.696 mol / 0.350 L
M = 1.99 M
Answer:
Na₂SO₃
Explanation:
We can use the <em>criss-cross method</em> to work out the formula.
1. Write the <em>symbols</em> of the anion and cation.
Na¹⁺ SO₃²⁻
2. <em>Criss-cross the numbers of the charge</em>s to become the subscripts of the other ion (see image).
3. Write the formula with the <em>new subscripts</em>.
Na₂(SO₃)₁
4. Omit all subscripts <em>that are 1.</em>
The formula becomes Na₂SO₃.
Answer:
H2 SO4 (Sulfuric acid) - HMnO4 (Permanganic acid) - HNO2 (Nitrous acid) HClO4 (Perchloric acid) - H2 SO3 (Sulphurous acid) - H2CrO4 (Chromic acid) H2CO3 (Carbonic acid) - HClO3 (Chloric acid) - H3BO3 (boric acid) - HClO2 (Chlorous acid) H3PO4 (Phosphoric acid) HNO3 (Nitric acid) - HClO (Hypochlorous acid) - CH3 COOH (acetic acid) - H2S2O3 (Thiosulfuric acid)- H2C2O4 (oxalic acid)
Explanation:
To name the ternary acid, they have to obbey the following formula
Hx - Non metal - Oy
where the oxidation state in H and O are +1 y -2 respectively.
When the oxidation state of the central Non metal is odd, the atomicity of H is 1 and in the O is deduced in such a way that the sum of oxidation states is 0.
When the oxidation state of the central No metal is even, the atomicity of H is 2 and in the O is deduced in such a way that the sum of oxidation states is 0.
IV V VI VII
- - 1 Hypo ……. Ous
- 3 4 3 … ous
4 5 6 5 … ic
7 Per …… Ous
The oxalic acid is an organic compound of two carboxyl groups, so it is also called ethanedioc acid; It is actually known as oxalic by some plants of the genus oxalis. (prefix et (2 carbons))
The acetic acid that comprises a carboxylic group and a methyl group is also an organic compound. It is popularly known as acetic acid but it is actually called methylcarboxylic acid or having two carbons, ethanoic acid.
Answer:
The answer to your question is V2 = 5.09 l
Explanation:
Data
Volume 1 = V1 = 5.0 L
Temperature 1 = T1 = 5°C
Volume 2 = V2 = ?
Temperature 2 = T2 = 10°C
Formula (Charles law)
V1/T1 = V2/T2
-Solve for V2
V2 = V1T2 / T1
-Convert temperature to °K
T1 = 5 + 273 = 278°K
T2 = 10 + 273 = 283°K
-Substitution
V2 = (5)(283) / (278)
-Simplification
V2 = 1415 / 278
-Result
V2 = 5.09 l
AlCl₃
Remember, you want to make their charges cancel. So, we need 3 chlorine atoms (because chlorine has a charge of -1) for every 1 aluminum atom (because aluminum has a charge of +3 ).
