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vivado [14]
3 years ago
7

Which is a function

Mathematics
2 answers:
RSB [31]3 years ago
8 0

Answer:

Function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable). Functions are ubiquitous in mathematics and are essential for formulating physical relationships in the sciences.

Step-by-step explanation:

d1i1m1o1n [39]3 years ago
3 0

Step-by-step explanation:

the second group. a function cannot have 2 of the same x values.

(7,9)

(20,14)

(9,-12)

(0,-9)

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(4x^2-2x-4)(2x+4) what is<br> the product of the polynomials below?
tatiyna

Answer:

8x³ + 12x² - 16x - 16

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Distributive Property

Step-by-step explanation:

<u>Step 1: Define expression</u>

(4x² - 2x - 4)(2x + 4)

<u>Step 2: Simplify</u>

  1. Expand:                                       8x³ - 4x² - 8x + 16x² - 8x - 16
  2. Combine like terms (x²):             8x³ + 12x² - 8x - 8x - 16
  3. Combine like terms (x):              8x³ + 12x² - 16x - 16
7 0
3 years ago
ASAP I WILL GIVE BRAINLIEST
hammer [34]

Answer:

8 inches

Step-by-step explanation:

V= Volume

A= Base

H= Height

<em>Formula: H= V÷A</em>

336in÷ 42in²= 8in

3 0
3 years ago
Glenda and Fiero are at a restaurant eating meal that costs $30. They have a discount coupon that gets them 10% off the cost. If
yaroslaw [1]

The cost of meal = $30

The tip to the waiter = 8%%

Discount = 10%%

Cost = 30 + 0.08 * 30 - 0.1 * 30

Cost = 30(1 + 0.08 - 0.1)

Cost = $$29.40

8 0
2 years ago
At a sale this week, a suit is being sold for $296.40. This is a 62% discount from the original price. What was the original pri
Soloha48 [4]
Suppose the original price to be x.
62%x=296.4
Divide both sides by 62% to get x=478, which is the original price.
7 0
3 years ago
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Integrate t sec^2 (2t) dt
Neporo4naja [7]
F = t ⇨ df = dt 
dg = sec² 2t dt ⇨ g = (1/2) tan 2t 
⇔ 
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt 
u = 2t ⇨ du = 2 dt 

As integral of tan u = - ln (cos (u)), you get : 

integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant 
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant 
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer 
8 0
4 years ago
Read 2 more answers
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