<span>A. Mechanic agitations</span>
The number of moles in monochloro pentaborane (9)
is 0.37056.
We know that ,
Number of moles = Given mass/ Molar mass
Given mass of monochloro pentaborane (9) is 20.1 g
The molar mass of monochloro pentaborane (9) is
= 
= 
= 54.241
Thus number of moles = 20.1/54.241
= 0.37056
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Mass/ energy can not be created or destroyed
Answer:
THE NEW VOLUME AT 1 K IS 1.2 L
Explanation:
Using Charles' law which states that the volume of a given gas is directly proportional to its temperature provided the pressure remains constant.
Mathematically written as;
V1/T1 = V2/T2 at constant pressure
V1 = Initial volume = 6L
T1 = initial temperature = 5K
T2 = Final temperature = 1K
V2 = final volume = unknown
Re-arranging the equation by making V2 the subject of the equation, we obtain;
V2 = V1 T2 / T1
V2 = 6 * 1 / 5
V2 = 1.2 L
The new volume of the gas sample at 1 K is 1,2 L