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Charra [1.4K]
2 years ago
5

Write an equation of a line that passes through (3,-2) and (-1,6).​

Mathematics
1 answer:
Zanzabum2 years ago
3 0

Answer:

-2x -y = -4

Step-by-step explanation:

the formula for calculating the equation of the line passing through two points is (look at the photo)

3 is x1, -2 is y1, -1 is x2 and 6 is y2

solve: x-3/-1-3 = y-(-2)/6-(-2)

x-3/-4 = y+2/8

transport the second fraction to the left of the equal, then it becomes negative:

x-3/-4 - y+2/8 = 0

do the mcm: -2(x-3)-(y+2) = 0

solve (minus in front of a parenthesis changes all signs inside it): -2x+6-y-2 = 0

-2x+4-y = 0

move the unknowns to the left of the equal:

-2x -y = -4

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Given:

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To find:

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According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

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Using (i), we get

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C(-2,11)\to C'(-2+4,3+2)

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Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

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A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

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(n-2)=3(2)

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