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Fantom [35]
3 years ago
6

How many one-thirds are in one-sixth?

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
6 0

Answer:

There r 6

Step-by-step explanation:

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What is the solution to the linear equation? x – StartFraction 2 Over 3 EndFraction x minus StartFraction one-half EndFraction e
Anton [14]

<em>Your question is not well presented</em>

Question:

What is the solution to the linear equation?

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Answer:

x = \frac{-5}{3}

Step-by-step explanation:

Given

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Required

Simplify

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Add \frac{1}{2} to both sides

x - \frac{2}{3}x - \frac{1}{2} + \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}

x - \frac{2}{3}x = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}

Subtract \frac{5}{6}x from both sides

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{5}{6}x + \frac{1}{2} - \frac{5}{6}x

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2} + \frac{5}{6}x- \frac{5}{6}x

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2}

Take LCMs

\frac{6x - 4x -5x}{6}= \frac{2+3}{6}

\frac{-3x}{6}= \frac{5}{6}

Multiply both sides by 6

6 * \frac{-3x}{6}= \frac{5}{6} * 6

-3x= 5

Divide both sides by -3

\frac{-3x}{-3}= \frac{5}{-3}

x = \frac{5}{-3}

x = \frac{-5}{3}

5 0
4 years ago
Read 2 more answers
24=3/4R.<br> Please reply step by step!
beks73 [17]

Answer:

r = 32

Step-by-step explanation:

R is the variable that we are trying to find.

24 = 3/4r

Since r is being multiplied by 3/4, we need to divide 3/4 on both sides to "undo" the multiplication.

24 / 3/4 = 3/4r / 3/4

32 = r

Therefore, r = 32.

To check, we can plug 32 into the equation.

24 = 3/4 x 32

3/4 x 32 = 24

8 0
2 years ago
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HELP!!! Worth 50 points
sergejj [24]

Answer:

with what

Step-by-step explanation:

I am confused there is no question at all showing

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3 years ago
Last question helo me pls
Yuri [45]
I hope this helps you

3 0
4 years ago
Write an equation of a line in slope-intercept form, which is passing through the point (8, −6) and is parallel to another line,
Tema [17]

Answer:Straight-line equations, or "linear" equations, graph as straight lines, and have simple variable expressions with no exponents on them. If you see an equation with only x and y – as opposed to, say x2 or sqrt(y) – then you're dealing with a straight-line equation.

There are different types of "standard" formats for straight lines; the particular "standard" format your book refers to may differ from that used in some other books. (There is, ironically, no standard definition of "standard form".)

Step-by-step explanation:

5 0
3 years ago
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