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rjkz [21]
3 years ago
15

How to find vertex form with vertex: (3,6) and y intercept: 2

Mathematics
1 answer:
bekas [8.4K]3 years ago
5 0

Answer:

<h3>              f(x) = - ⁴/₉(x - 3)² + 6</h3>

Step-by-step explanation:

The vertex form of  the equation of the parabola with vertex (h, k)  is:

f(x) = a(x - h)² + k

So for vertex (3, 6) it will be:

f(x) = a(x - 3)² + 6

<u>y intercept: 2</u> means  f(0) = 2

f(0) = a(0 - 3)² + 6

2 = a(-3)² + 6

2 -6 = 9a + 6 -6

-4 = 9a

a = ⁻⁴/₉

Therefore:

The vertex form of quardatic function with vertex: (3,6) and y intercept: 2 is

                             <u>f(x) = - ⁴/₉(x - 3)² + 6</u>

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