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3 years ago

Find the slop on the graph rise run m =

Mathematics

1 answer:

34kurt3 years ago

6 0

Answer:

There is no graph

Step-by-step explanation:

*I see

*I think

*I think before I speak

*I say " There is no graph

I try to make people laugh when they mess up a little, we all mess up

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The function G(x)=f(x+3)+2 which of the following is true of the graph of g(x)?

zepelin [54]

G(x)=(x+3)+2

G(x) = (x-h) + k
h translates the graph left/right and k translates the graph up/down.
Because the equation is x- the parenthesis is (x - - 3) which makes h a negative 3 and will translate left. The k positive so it will move up.
Letter B

7 0

3 years ago

What is the value of x with clear working out please?

nirvana33 [79]

Answer:

Answer:  x is 46° 

Step-by-step explanation:

• Let's first find Angle ACB

${ \rm{ \angle ACB + 23 \degree + 90 \degree = 180 \degree}} \\ \\ { \rm{ \angle ACB = (180 - 90 - 23) \degree}} \\ \\ { \underline{ \rm{ \: \angle ACB = 67 \degree}}}$

• From alternative angles, x = Angle BAC.

• Since AB = AC, then Angle ABC = Angle ACB

${ \rm{x + \angle ABC + \angle ACB = 180 \degree}} \\ \\ { \rm{x + 67 \degree + 67 \degree = 180 \degree}} \\ \\ { \rm{x + 134 \degree = 180 \degree}} \\ \\ { \boxed{ \rm{x = 46 \degree}}}$

5 0

2 years ago

Read 2 more answers

In music, what does "allegro" mean?

Cerrena [4.2K]

Having a quick, lively tempo. Typically considered to be faster than allegretto, but slower than presto.

8 0

3 years ago

Can someone please help me.

skelet666 [1.2K]

To find the slope of the line, you need two points.
(-2 , 5) and (3 , -5)

5 - (-5) / -2 - 3
10 / -5 = -2

The slope of the line is -2. So your answer is C.

8 0

3 years ago

It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando

notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, $\overline x_1$ = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, $\overline x_2$ = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀: $\overline x_1$ = $\overline x_2$

The alternative hypothesis, Hₐ: $\overline x_1$ ≠ $\overline x_2$

The pooled variance, $S_p^2$ , is given as follows;

$S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}$

Therefore, we have;

$S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682$

The test statistic is given as follows;

$t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}$

Therefore, we have;

$t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176$

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0

2 years ago