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3 years ago

Find the slop on the graph rise run m =

Mathematics

1 answer:

34kurt3 years ago

6 0

Answer:

There is no graph

Step-by-step explanation:

*I see

*I think

*I think before I speak

*I say " There is no graph

I try to make people laugh when they mess up a little, we all mess up

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A ribbon is 12 3/8 feet long.Into how many 3/4-foot pieces can it be cut?

seraphim [82]

12 3/8 ÷ 3/4

change the mixed fraction to improper....

99 3
__ ÷ __
8 4

now change the sign to a multiplication sign and flip 3/4.

99 4 396
__× __= _____
8 3 24

396/24..... that changes to 16 22/24. Simplify it and it will be 16 11/12.

6 0

4 years ago

-3/7 + -3/4 by today Plus points

Roman55 [17]

Answer:

-33/28

Step-by-step explanation:

-12/28 + -21/28

= -33/28

you can't simplify it so its -33/28

6 0

3 years ago

Read 2 more answers

The height of a cone is twice the radius of its base.

lara [203]

Answer:

$A. \frac{2}{3} \pi x^3$

Step-by-step explanation:

From the way the answers are presented, it can be seen that x refers to the radius of the base of the cone

radius: $x$

and we are told that the height is twice the radius, so:

height: $2x$

and now we use the formula to calculate the volume of a cone:

$V=\frac{\pi r^2h}{3}$

where $V$ is volume, $r$ is radius, and $h$ is the height. and $\pi$ is a constant

in this case

$r=x$

$h=2x$

so we substitute thisvalues in the formula for the volume:

$V=\frac{\pi x^2(2x)}{3}$

Rearranging the terms

$V=\frac{2\pi x^3}{3} \\V=\frac{2}{3} \pi x^3$

which is option A.

6 0

3 years ago

A motorboat that travels with a speed of 20 km/hour in still water has traveled 20 km against the current and 180 km with the cu

Gala2k [10]

Recall your d = rt. distance = rate * time.

let's say the speed of the current is "c".

keeping in mind that, when the boat is going against the current, the boat is not really going at 2kmh, but instead at " 20 - c ", because the current is subtracting speed from it.

Likewise when is going with the current, is going at a speed of " 20 + c ".

if the boat took say "t" hours on the way over, on the way back it took the slack from the whole 8 hours and "t", namely it took " 8 - t " hours.

$\bf \begin{array}{lccclll}
&\stackrel{km}{distance}&\stackrel{kmh}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{against the current}&20&20-c&t\\
\textit{with the current}&180&20+c&8-t
\end{array}
\\\\\\
\begin{cases}
20=(20-c)(t)\implies \frac{20}{20-c}=t\\
180=(20+c)(8-\stackrel{\downarrow }{t})\\
--------------\\
180=(20+c)\left( 8- \stackrel{\downarrow }{\frac{20}{20-c}}\right)
\end{cases}
\\\\\\
180=(20+c)\left( \cfrac{(160-8c)-20}{20-c} \right)$

$\bf 180=(20+c)\left( \cfrac{140-8c}{20-c} \right)\implies 180(20-c)=(20+c)(140-8c)
\\\\\\
3600c-180c=2800-160c+140c-8c^2
\\\\\\
3600c-180c=2800-20c-8c^2
\\\\\\
3600c-180c-2800+20c+8c^2=0\implies 8c^2-160c+800=0
\\\\\\
c^2-20c+100=0\implies (c-10)(c-10)=0\implies \boxed{c=10}$

8 0

3 years ago

Find 3 fractions that are equivalent to 3/8. explain your method

Nikolay [14]

Hey Aarya!

If we `scale` both the numerator and denominator by the same value, then we can create other equivalent fractions. By scale I mean: Multiply both the top and bottom of the fraction by the same value.

So here is one we can try.
Let's multiply numerator and denominator by 3.
$\rm \frac38\cdot\frac33=\frac9{24}$
Yay we did it! We found another fraction which is equivalent to 3/8.

5 0

3 years ago