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attashe74 [19]
3 years ago
15

Which statement describes the Arrhenius interpretation of acids and bases?

Chemistry
1 answer:
murzikaleks [220]3 years ago
6 0

Answer: Composition is an orderly arrangement of visual structures (elements and principles) to create a mood, add meaning and direct the viewers' attention to the purpose of the artwork. Compositions are said to be 'designed' according to the specific intent of the artist.

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Convert 10erg into joule​
Luden [163]

Answer:

0.000001 joule

Explanation:

brainlest?

5 0
3 years ago
Osmium has a density of 22.6 g/cm^3. What volume (in cm^3) would be occupied by a 21.8 g sample of osmium?
Snowcat [4.5K]

0.9645 cm³ is the occupied volume by a 21.8 g sample of osmium of density of 22.6 g/cm^3.

Given values are:

  • Mass, m = 21.8 g
  • Density, d = 22.6 g

Density is given by,

  density = \frac{mass}{volume}

⇒volume = \frac{mass}{volume}

⇒volume = \frac{21.8}{22.6}

⇒volume = 0.9645 cm^3

∴The volume is 0.9645cm^3

To learn more about Density: brainly.com/question/15164682     #SPJ4

6 0
2 years ago
Help on science please!
erik [133]

Answer:

See explanation.

Explanation:

1. Forrest: From 425,000,000 to 300,000,000 is a change of 125,000,000. Divide the 125,000,000 by 425,000,000 to get the percent change:

125,000,000 / 425,000,000 = .294, which is a 29.4% change, a decrease.

2. Population: From 4,500 to 326,500,000 is a change of 326,495,500. Divide 326,495,500 by 4,500 to get the percent change.

326,495,500 / 4,500 = 72,554.55 which is a change of 7,255,455% change, an increase.

3. Conclusion: The growth in population required living area. People needed farms, houses, cities, and communities to live in. Forests were cleared to make room for the people to live. Forests are also used to provide building materials. The population increase contributed to the decrease in forest lands.

6 0
3 years ago
A black rooster mates with a white hen. Based on their genotypes, the chance that the offspring will be checkered is 100 percent
zheka24 [161]

Answer: BB is rooster.

bb is hen

6 0
3 years ago
Read 2 more answers
The molar absorptivity of a tyrosine residue at 280 nm is 2000 M-1cm-1, while for tryptophan it is 5500 M-1cm-1. A protein has b
adelina 88 [10]

Answer:

There are 4 tryptophans in the protein.

Explanation:

According to question,  protein contains one tyrosine residue and say x number of tryptophans.

Concentration of protein solution = 1.0 micromolar = 1.0\times 10^{-6} Molar

Molar absorptivity of a protein solution : \epsilon

\epsilon = \epsilon _{tyro}+\epsilon _{tryp}

=1\times 2000 M^{-1}cm^{-1}+x\times 5500 M^{-1}cm^{-1}

Length of the cuvette = l = 1.0 cm

Absorbance of protein solution at 280 nm = A = 0.024

A=\epsilon \times l\times c ( Beer-Lambert's law)

0.024=(1\times 2000 M^{-1}cm^{-1}+x\times 5500 M^{-1}cm^{-1})\times 1 cm\times 1.0\times 10^{-6} M

Solving for x :

x = 4

There are 4 tryptophans in the protein.

7 0
3 years ago
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