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attashe74 [19]
3 years ago
15

Which statement describes the Arrhenius interpretation of acids and bases?

Chemistry
1 answer:
murzikaleks [220]3 years ago
6 0

Answer: Composition is an orderly arrangement of visual structures (elements and principles) to create a mood, add meaning and direct the viewers' attention to the purpose of the artwork. Compositions are said to be 'designed' according to the specific intent of the artist.

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What is the maximum number of electrons that can be contained in the first, second, third, and fourth energy levels, respectivel
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It can be determined by 2n^2 formula 
where "n" is the no of shell:
1st shell = 2n^2 = 2(1)^2 = 2*1 = 2 electrons
2nd shell = 2n^2 = 2(2)^2 = 2*4 = 8 electrons
3rd shell = 2n^2 = 2(3)^2 = 2*9 = 18 electrons
4th shell = 2n^2 = 2(4)^2 = 2*16 = 32 electrons.
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3 years ago
(a) How much negative charge is on each oxygen of the carbonate ion?
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The chemical formula of a carbonate ion is CO3^2-. It is an AX3 system which means it take the trigonal planar shape. There would be two single bonds of C-O and one double bond C-O in order for C to agree with the octet rule. Two minus charges are equally distributed to the three oxygen atoms so that each oxygen of the carbonate ion would have a charge of negative 2/3.
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3 years ago
What is the correct notation for a calcium ion whose outershell is a full octet?
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8 0
3 years ago
Write a balanced equation for the combustion of C7H16(l) (heptane) -- i.e. its reaction with O2(g) forming the products CO2(g) a
JulsSmile [24]

Answer:

<u>The standard enthalpy of reaction = -4854.7kJ</u>

<u>The difference: </u>ΔH-ΔE = Δ(PV) = Δn.R.T = <u>9910.288 J ≈ 9.91 kJ</u>    

Explanation:

<u>The balanced chemical equation for the combustion of heptane</u>:

C₇H₁₆ (l) + 11 O₂ (g) → 7 CO₂ (g) + 8 H₂O (l)

Given: The standard enthalpy of formation (\Delta H _{f}^{\circ }) for: C₇H₁₆ (l) = -187.8 kJ/mol, O₂ (g) = 0 kJ/mol, CO₂ (g) = -393.5 kJ/mol, H₂O (l) = -286 kJ/mol

<u>To calculate the standard enthalpy of reaction (\Delta H _{r}^{\circ }) can be calculated by the Hess's law</u>:

\Delta H _{r}^{\circ } = \left [\sum \nu \cdot\Delta H _{f}^{\circ }(products)  \right ] - \left [\sum \nu\cdot\Delta H _{f}^{\circ }(reactants)  \right ]

Here, \nu is the stoichiometric coefficient

⇒ \Delta H _{r}^{\circ } =

\left [ 7\times \Delta H _{f}^{\circ }\left (CO_{2}\right )+ 8\times \Delta H _{f}^{\circ }\left (H_{2}O \right )\right ]

- \left [1\times \Delta H _{f}^{\circ }\left (C_{7}H_{16}\right ) +11\times \Delta H _{f}^{\circ }\left (O_{2} \right ) \right ]

=\left [ 7\times \left (-393.5 kJ/mol \right )+ 8\times \left (-286 kJ/mol \right )\right ]

-\left [1\times \left (-187.8 kJ/mol \right ) +11\times \left (0 kJ/mol \right ) \right ]

⇒ \Delta H _{r}^{\circ } = \left [ \left (-2754.5 \right )+ \left (-2288 \right )\right ]\left -[ \left (-187.8 \right ) +\left (0 \right )\right ]

⇒ \Delta H _{r}^{\circ } = \left [ -5042.5 ]\left -[ -187.8] = \left ( -4854.7kJ \right )

<u>To calculate the difference: </u>ΔH-ΔE=Δ(PV)

We use the ideal gas equation: P.V = n.R.T

⇒ ΔH-ΔE=Δ(PV) = Δn.R.T

Given: Temperature:T = 298K, R = 8.314 J⋅K⁻¹⋅mol⁻¹

Δn = number of moles of gaseous products - number of moles of gaseous reactants = (7)- (11) = (-4)

⇒ ΔH-ΔE=Δ(PV) = Δn.R.T = (-4 mol) × (8.314 J⋅K⁻¹⋅mol⁻¹) × (298K) = <u>9910.288 J = 9.91 kJ</u>                              (∵ 1 kJ = 1000J )

                                                                             

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3 years ago
How does the motion of the particles change when thermal energy added
Sonbull [250]
The particles move faster when more thermal energy is added creating heat.
6 0
3 years ago
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