Answer:
308 g
Explanation:
Data given:
mass of Fluorine (F₂) = 225 g
amount of N₂F₄ = ?
Solution:
First we look to the reaction in which Fluorine react with Nitrogen and make N₂F₄
Reaction:
2F₂ + N₂ -----------> N₂F₄
Now look at the reaction for mole ratio
2F₂ + N₂ -----------> N₂F₄
2 mole 1 mole
So it is 2:1 mole ratio of Fluorine to N₂F₄
As we Know
molar mass of F₂ = 2(19) = 38 g/mol
molar mass of N₂F₄ = 2(14) + 4(19) =
molar mass of N₂F₄ = 28 + 76 =104 g/mol
Now convert moles to gram
2F₂ + N₂ -----------> N₂F₄
2 mole (38 g/mol) 1 mole (104 g/mol)
76 g 104 g
So,
we come to know that 76 g of fluorine gives 104 g of N₂F₄ then how many grams of N₂F₄ will be produce by 225 grams of fluorine.
Apply unity formula
76 g of F₂ ≅ 104 g of N₂F₄
225 g of F₂ ≅ X of N₂F₄
Do cross multiplication
X of N₂F₄ = 104 g x 225 g / 76 g
X of N₂F₄ = 308 g
So,
308 g N₂F₄ can be produced from 225 g F₂
Answer:
2nd one down
Explanation: distance divided by time interval
Answer:
Centripetal acceleration of the wheel is
.
Explanation:
We have,
Diameter of a Ferris wheel is 60 m
Radius of the wheel is 30 m
Speed of the wheel is 2.09 m/s
It is required to find the centripetal acceleration of the wheel. The formula of centripetal acceleration is given by :

So, the centripetal acceleration of the wheel is
.
Answer:
The rate of change of the temperature is 0.0365 Kelvin per minute.
Explanation:
<u>Step 1</u>: Given data
ideal gas law: P*V = n*R*T
with P= pressure of the gas ( in atm) = 9.0 atm
with V= volume of the gass (in L) =12L
with n = number of moles = 10 moles
R = gas constant = 0.0821 L*atm* K^−1*mo^−1
T = temperature = TO BE DETERMINED
The volume decreases with a rate of 0.17L/min = dV/dT = -0.17
The pressure increases at a rate of 0.13atm/min = dP/dT
<u>Step 2:</u> The ideal gas law
P * [dV/dT] + V * [dP/dT] = nR * dT/dt
9 atm * (-0.17L/min) + 12L * 0.13atm/min = 10 moles * 0.0821 L*atm* K^−1*mo^−1 *dT/dt
0.03 = 0.821 * dT/dt
dT/dt = 0.03/0.821
dT/dt = 0.0365
Since the gas constant is expressed in Kelvin and not in °C, this means that <u>the rate of chagnge of the temperature is 0.0365 Kelvin per 1 minute.</u>
IM THINKING THEY BELONG IN THIS CLASS OF ELEMENTS VILL B.
Hope i Helped