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satela [25.4K]
3 years ago
13

a student takes three beakers and places 250 ml of water in each. the student then adds a cube of sugar to all three beakers. th

e first beaker is stirred, the second beaker is heated, and the third is left alone. which of the following statements is true? the first beaker dissolves faster than the other two. the second beaker dissolves faster than the other two. the third beaker does not dissolve as fast as one and two. there is not enough information to determine the answer.
Chemistry
2 answers:
Olegator [25]3 years ago
6 0
The third beaker doesnt dissolve as fast as one and two

as it has nothing changed to it

when you stir it gives the sugar more kinetic energy to dissolve
when you heat up the solution it also gives the sugar more kinetic energy

hope that helps 
rjkz [21]3 years ago
6 0

Answer : The correct statement is, the third beaker does not dissolve as fast as one and two.

Explanation :

According to the question, we know that the dissolving process is faster in case of heating as compared to the stirring. And the dissolving process also depends on the how much amount of heat are provided to the substance or the how much faster will you stirring mixture.

The second beaker dissolves faster than the other two, this statement is true but we do not know the how much heat are given to the beaker.

From the given statements we conclude that the correct statement is, the third beaker does not dissolve as fast as first and second beakers because in the third beaker there is no heat or mechanical energy are provided for mixing of the substance.

Hence, the correct statement is, the third beaker does not dissolve as fast as one and two.

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Mannoheptulose is a sugar found in avocados. If each C-C bond contains 76 kcal of energy and each C-H bond contains 91 kcal, how
nadya68 [22]

Answer:

Total Kcal energy produced in the catabolism of mannoheptulose = 1184 Kcal

Explanation:

The molecular formula of mannoheptulose is C₇H₁₄O₇.

The structure is as shown in the attachment below.

Number of C-C bonds present in mannoheptulose = 6

Number of C-H bonds present in mannoheptulose = 8

Since the each C-C bond contains 76 Kcal of energy,

Amount of energy present in six C-C bonds = 6 * 76 = 456 Kcal

Also, since each C-H bond contains 91 Kcal of energy;

amount of energy present in eight C-H bonds = 8 * 91 = 728 Kcal

Total Kcal energy produced in the catabolism of mannoheptulose = 456 + 728 = 1184 Kcal

6 0
2 years ago
What does it mean to say B is representing the dominant gene
Degger [83]

Answer:

Dominant genes are always represented by a capital letter which in this case is the letter B whereas recessive genes will be represented by a lower case letter like b.

You only need one copy of a dominant gene or allele to inherit it. A dominant allele is always expressed even if only one copy is present.

But you need two copies of genes or alleles to inherit the recessive gene. There also can't be a dominant allele of the gene if you are to inherit this.

Allele - Different forms of a gene

8 0
3 years ago
What is a covenant bond
kramer

Answer:

Explanation:

I think you meant a covalent bond, a bond between two non-metal atoms. This image can explain better than I can.

4 0
3 years ago
How many grams of Carbon are in sample of 400 grams of Co2?​
RoseWind [281]

Answer:

Mass of carbon = 109.1 g

Explanation:

Given data:

Mass of carbondioxide = 400 g

Mass of carbon = ?

Solution:

Molar mass of carbon = 12 g/mol

Molar mass of CO₂ = 44 g/mol

Mass of carbon in 400g of  CO₂:

Mass of carbon = 12 g/mol/44 g/mol × 400 g

Mass of carbon = 109.1 g

3 0
3 years ago
A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure
GenaCL600 [577]

Answer:

P_A=4.20atm\\\\P_B=17.1atm

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

PV=nRT

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm

Best regards!

8 0
3 years ago
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