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miv72 [106K]
3 years ago
13

When coal or oil are burned, some part of it is completely combusted, forming co2; another part is partially combusted, forming

co (carbon monoxide); and some remains unburned and is released as soot. along with sulfur dioxide, these are the main components of?
Chemistry
1 answer:
Arturiano [62]3 years ago
6 0
These are main components of Industrial Smog. Smog is air pollutant. Main sources of Smog are 1) Coal, 2) Transportation Emission, 3) Natural Causes. Those areas are mainly effected which are located in Industrial Zones and those which has high traffic density. Cities like Delhi, Beijing, London, Maxico City, Log Angeles, Tehran e.t.c are reported to be highly effected by smog. Among these polutants, CO₂ is the main source of Global Warming, CO has adverse effects on human health as it has 200 times more potency to bind with Hemoglobin compared to Oxygen, SO₂ when present in air reacts with water producing acid rain e.t.c.
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Write a word equation for the chemical reaction.<br><br> I’ll brainlist.
Alex

Answer:

potassium hydroxide + sulfuric acid → potassium sulfate + water.

Explanation:

Hope it helps.. if yes, plz mark me as brainliest

5 0
3 years ago
For a particular reaction, ΔH=−111.4 kJ/mol and ΔS=−25.0 J/(mol·K).
PtichkaEL [24]
That’s the answer ^^^^
3 0
3 years ago
If the molar absorptivity constant for the red dye solution is 5.56×104 M-1cm-1, calculate the molarity of the red dye solution
Shtirlitz [24]

Explanation:

a) Using Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

where,

A = absorbance of solution = 0.945

c = concentration of solution = ?

l = length of the cell = 1.20 cm

\epsilon = molar absorptivity of this solution =5.56\times 10^4 M^{-1} cm^{-1}

0.945=5.56\times 10^4 M^{-1} cm^{-1}\times 1.20 \times c

c=1.4163\times 10^{-5} M=14.16 \mu M

(1\mu M=10^{-6} M)

14.16 μM is the molarity of the red dye solution at the optimal wavelength 519nm and absorbance value 0.945.

b) c=1.4163\times 10^{-5} mol/L

1 L of solution contains 1.4163\times 10^{-5} moles of red dye.

Mass of 1.4163\times 10^{-5} moles of red dye:

1.4163\times 10^{-5}\times 879.86g/mol=0.01246 g

(w/v)\%=\frac{\text{Mass of solute (g)}}{\text{Volume of solvent (mL)}}\times 100

red(w/v)\%=\frac{0.01246 g}{1000 mL}\times 100=0.001246\%

c) In order to dilute red dye solution by 5 times, we will need to add 1 L of water to solution of given concentration.

Concentration of red dye solution = c=1.4163\times 10^{-5} M

Concentration of red solution after dilution = c'

c=c'\times 5

1.4163\times 10^{-5} M=c'\times 5

c'=2.83\times 10^{-6} M

The final concentration of the diluted solution is 2.83\times 10^{-6} M

8 0
3 years ago
Pls answer this two ASAP PLSSSSSSSS
d1i1m1o1n [39]

Answer:

1. aa

2. They have similar DNA

Explanation:

1. According to the question 1, wrinkled seeds (A) are dominant over round seeds (a) in pea plants. This means that, based on the law of dominance proposed by Mendel, wrinkled seeds will be expressed over round seeds in a heterozygous state (Aa).

However, since the round seed phenotype is a recessive trait, it will only be expressed when the alleles for round seeds (a) are the same in the gene i.e. aa genotype.

2. Based on the information in question 2, Ricky, who is working on a family tree for his school project, realizes that his close relatives all look similar in the pictures he collected. This is possible because of the SIMILARITY OF THEIR DNA (genetic material). Note that, relatives are connected by the genes that are inherited from one another, hence, they possess a similar DNA, which is the most valid reason for the resemblance.

4 0
2 years ago
Which of the following equations follows the law of conservation of mass?
Dovator [93]

Answer:

option A = C₂H₄ + 3O₂   →    2CO₂   +  2H₂O

Explanation:

Law of conservation of mass:

This law stated that mass can not be created or destroyed in chemical reaction. It just changed from one to another form.

For example:

C₂H₄   +   3O₂   →    2CO₂   +  2H₂O

28 g   + 96 g    =      88 g  +  36 g

    124  g           =      124 g

This reaction correctly hold the law of conservation of mass.

Other options:

C  + 4H₂  →   CH₄

12 g  + 8g  = 16 g

  20 g  =   16 g

This reaction do not hold the law of conservation of mass.

3H₂O  →   3H₂  +  3O₂

  54 g  =   6 g +  96 g

   54 g =   102 g

This reaction do not hold the law of conservation of mass.

2Na  +  Cl  →  NaCl

46 g  + 35.5 g  =   58.5 g

  81.5 g = 58.5 g

This reaction do not hold the law of conservation of mass.

6 0
3 years ago
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