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VikaD [51]
3 years ago
12

BRAINLIEST/BRAINLIEST/ Please help

Physics
1 answer:
Alexxx [7]3 years ago
8 0

Answer:

1. the pressure inside any enclosures on the moon as the sun hits the exterior and the temperature begins to rise is going to increase, you could use an air pump to lower the pressure in the room.

2. you could put them in jars, I once saw people selling Jarred air supposedly from Honolulu, Hawaii, but they didn't seem to do that well for some reason XD. or if you are staying long term in space, you could bring a couple of plants and plant them if you want, that what NASA did.

3. you could try removing the carbon dioxide with canisters that contain powdered lithium hydroxide. When air containing carbon dioxide gets passed through the canister, it combines with the lithium hydroxide to form lithium carbonate and water. you could dump the lithium carbonate and water into space and make space trash if you don't want them taking up too much space, water will probably freeze or something if you launch it into space due to the temperature out there.

Explanation:

can I have brainiest pls? this took me like half an hour

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g A circular loop of wire with radius 3 m is flat on the xy plane in a magnetic field which is pointed in the z-direction and ha
Phantasy [73]

Answer:

emf=-0.035V

Explanation:

this problem can be solved with the Lenz's law:

emf=-\frac{\Delta \Phi_{B}}{\Delta t}

where PhiB is the magnetic flux. In this case we have

\Delta \Phi_{B}=B(A_1-A_2)

due to the magnetic field is constant. A is the area of the circular loop. Hence

\Delta \Phi_{B}=(5*10^{-3}T)(\pi(3m)^2-\pi(1.5m)^2)=0.106Tm^2

Finally

emf=-\frac{0.106Tm^2}{3s}=-0.035V

HOPE THIS HELPS!!

7 0
3 years ago
(b) Released from rest at the same height, a can of frozen juice rolls to the bottom of the same hill. What is the translational
Oksanka [162]

Answer:

Explanation:

a) using the energy conservation  equation

mgh = 0.5mv^2 + 0.5Iω^2

I(moment of inertia) (basket ball) = (2/3)mr^2

mgh = 0.5mv^2 + 0.5( 2/3mr^2) ( v^2/r^2)

gh = 1/2v^2 + 1/3v^2

gh = v^2( 5/6)

v =  \sqrt{\frac{6gh}{5} }

putting the values we get

6.6 ^{2} = \frac{6\times9.8h}{5}

solving for h( height)

h = 3.704 m apprx

b) velocity of solid cylinder

mgh = 0.5mv^2 + 0.5( mr^2/2)( v^2/r^2) where ( I ofcylinder = mr^2/2)

g*h = 1/2v^2 + 1/4v^2

g*h = 3/4v^2

putting the value of h and g we get

v= = 6.957 m/s apprx

5 0
4 years ago
Please Help!!! Max points!!!!!!
svp [43]

Answer:

some kind of change

motion

KE = 1/2 m v^2

velocity

drag/air resistance

size

shape

Explanation:

8 0
3 years ago
A mass is oscillating up and down on a spring. In the above graph of
melomori [17]

Answer:

<em>Amplitude= 8 m</em>

Explanation:

<u>The Amplitude of a Wave</u>

Sinusoidal Function  refers to a mathematical curve with a smooth and periodic oscillation. Its name comes from the sine function and is characterized by the amplitude or the maximum displacement or distance moved by a point on a vibrating body measured from its equilibrium position.

To calculate the amplitude from a graph, we measure the maximum point and the minimum point the wave reaches. Then we subtract both values and divide the result by 2.

The shown wave in the figure has a maximum value of 8 m and a minimum value of -8 m. The distance from the maximum to the minimum is 8-(-8)= 16 m, thus the amplitude is 16/2= 8m.

Amplitude= 8 m

5 0
3 years ago
An object at rest does not _____ and an object in motion does not _____, unless an _____ force acts upon it
mel-nik [20]

Answer:

An object at rest does not move and an object in motion does not change its velocity, unless an external force acts upon it

Explanation:

This statement is also known as Newton's first law, or law of  inertia.

It states that the state of motion of an object can be changed only if there is an external force (different from zero) acting on it: therefore

- If an object is at rest, it will remain at rest if there is no force acting on it

- If an object is moving, it will continue moving at constant velocity if there is no force acting on it

This phenomenon can be also understood by looking at Newton's second law:

F = ma

where

F is the net force on an object

m is the mass

a is the acceleration

If the net force is zero, F = 0, the acceleration of the object is also zero, a = 0: therefore, the velocity of the object does not change, and it will continue moving at the same velocity (which can be zero, if the object was at rest).

5 0
3 years ago
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