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liraira [26]
3 years ago
12

Which expression is equivalent to 5(2+7)? 0 2(5+7) O 2 + 7(5) O 5(2)+7 O 5(2)+5(7)​

Physics
1 answer:
professor190 [17]3 years ago
6 0

Answer:

5(2)+5(7)

Explanation:

5(2)+5(7)=10+35=45

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A cart with mass m vibrating at the end of a spring has an extra block added to it when its displacement is x=+A. What should th
Pavel [41]

Answer:

The block's mass should be 3m

Explanation:

Given:

Cart with mass m

From the conservation of energy before mass is added,

  \frac{1}{2} mv^{2} = \frac{1}{2} kA^{2}

Where A = amplitude of spring mass system, k = spring constant

  A = v\sqrt{\frac{m}{k} }

Now new mass M is added to the system,

   \frac{1}{2} (m +M ) v^{2}  = \frac{1}{2}  k A^{2}

  A = v \sqrt{\frac{m +M }{k} }

Here, given in question frequency is reduced to half so we can write,

   f' = \frac{f}{2}

Where f = frequency of system before mass is added, f' = frequency of system after mass is added.

        \omega ' = \frac{\omega}{2}

\sqrt{\frac{k}{m +M} }  = \frac{\sqrt{\frac{k}{m} } }{2}

   \frac{k}{m +M } = \frac{k}{4m}

   M = 3m

Therefore, the block's mass should be 3m

8 0
3 years ago
The Capacitive reactance of a 0.094uF capacitor when a frequency of 25kHz is applied is lus 68 Ohms 0.68 Ohms luf
Nana76 [90]

Answer:

Capacitive reactance of the capacitor is 68 ohms

Explanation:

It is given that,

Capacitance, C=0.094\ \mu F=0.094\times 10^{-6}\ F

Frequency, f=25\ kHz=25\times 10^3\ Hz

Capacitive reactance is given by :

X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi 25\times 10^3\times 0.094\times 10^{-6}}

X_C=67.72\ \Omega

or

X_C=68\ \Omega

So, the capacitive reactance of the capacitor is 68 ohms. Hence, this is the required solution.

8 0
3 years ago
Which of the following prefixes represents the largest value
Zigmanuir [339]
C should be right ok



7 0
3 years ago
The moon at on atmosphere​
borishaifa [10]

Answer:

please write the question by our way which we can understand

6 0
3 years ago
What can you say about a solution of the equation y' = (1/2)y2 just by looking at the differential equation?
noname [10]

The function y must be equal to 0 on any interval on which it is defined. The function y must be increasing (or equal to 0) on any interval on which it is defined.

Analysis of solution by seeing differential equation:

Given differential equation is: y' = (1/2)y2

How do deduce the results just by seeing them?

The equation tells us that:

rate = positive of ( y^2 )

rate = positive of (positive or zero) = positive or zero

Thus, the rate is positive or zero no matter what value we put in the place of y from its valid domain, since.

When the rate is positive or zero, that means the function will never grow upwards. Thus, either increasing or staying at the same level.

Learn more about differential equations here:

brainly.com/question/25731911

#SPJ4

6 0
2 years ago
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