Atoms begin to gravitate together to form a center
Answer:
The answer is the 1st one
Answer: 7200 m
Explanation: The solution is, first convert 15 minutes to seconds.
15 mins x 60 s / 1 min = 900 s
Use the formula for speed which is v= d/t then derive for d.
d = vt
= 8 m/s ( 900s)
= 7200 m
Answer: Because the fuse can disconnect the circuit only when the excess current flows completely through the neutral. ... Since, neutral is not a live conductor coming from the source, disconnecting a neutral line can only open the current path through neutral. But, the live phase still carries the charge.
Explanation:
Horizontal speed = 24.0 m/s
height of the cliff = 51.0 m
For the initial vertical speed will are considering the vertical component. Therefore,
Since the student fires the canonical ball at the maximum height of 51 m, the initial vertical velocity will be zero. This means

let's find how long the ball remained in the air.
![\begin{gathered} 0=51-\frac{1}{2}(9.8)t^2 \\ 4.9t^2=51 \\ t^2=\frac{51}{4.9} \\ t^2=10.4081632653 \\ t=\sqrt[]{10.4081632653} \\ t=3.22 \\ t=3.22\text{ s} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%200%3D51-%5Cfrac%7B1%7D%7B2%7D%289.8%29t%5E2%20%5C%5C%204.9t%5E2%3D51%20%5C%5C%20t%5E2%3D%5Cfrac%7B51%7D%7B4.9%7D%20%5C%5C%20t%5E2%3D10.4081632653%20%5C%5C%20t%3D%5Csqrt%5B%5D%7B10.4081632653%7D%20%5C%5C%20t%3D3.22%20%5C%5C%20t%3D3.22%5Ctext%7B%20s%7D%20%5Cend%7Bgathered%7D)
Finally, let's find the how far from the base of the building the ball landed(horizontal distance)