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Karolina [17]
3 years ago
15

What has westpac stadium in wellington got to do with the structure of a hydrogen atom

Physics
1 answer:
bixtya [17]3 years ago
7 0

What has Westpac Stadium in Wellington got to do with the structure of a hydrogen atom? A grain of rice placed in the centre of the field represents the nucleus.

but am not sure if thats right

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How does an atom of chlorine-37 become a chloride ion with a -1 charge?
kirill115 [55]

Answer:

B. The atom gains 1 electron, to make a total of 18 electrons.

Explanation:

Chlorine is the 17th element in the periodic table, so it has atomic number 17:

Z = 17

This means that a neutral atom of chlorine has 17 protons and 17 electrons.

When a chlorine atom gains 1 electron, its electric charge (initially zero) becomes -1, since the electron has negative charge of -1 (in elemntary charge units). This also means that the number of electrons in the ion is now

17 + 1 = 18

So the correct answer is

B. The atom gains 1 electron, to make a total of 18 electrons

5 0
3 years ago
How many times can energy be transformed?
kykrilka [37]
Only once hope this helps
7 0
3 years ago
Read 2 more answers
To win the game, a placekicker must kick a football from a point 44 m (48.1184 yd) from the goal, and the ball must clear the cr
Ganezh [65]

Answer:

The distance by the ball clear the crossbar is 1.15 m

Explanation:

Given that,

Distance = 44 m

Speed = 24 m/s

Angle = 31°

Height = 3.05 m

We need to calculate the horizontal velocity

Using formula of horizontal velocity

u_{x}=u\cos\theta

Put the value into the formula

u_{x}=24\cos(31)

u_{x}=20.5\ m/s

We need to calculate the vertical velocity

Using formula of vertical velocity

u_{y}=u\sin\theta

Put the value into the formula

u_{y}=24\sin(31)

u_{y}=12.3\ m/s

We need to calculate the time

Using formula of time

t=\dfrac{d}{u_{x}}

Put the value into the formula

t=\dfrac{44}{20.5}

t=2.1\ sec

We need to calculate the vertical height

Using equation of motion

h=u_{y}t+\dfrac{1}{2}at^2

Put the value into the formula

h=12.3\times2.1-\dfrac{1}{2}\times9.8\times(2.1)^2

h=4.2\ m

We need to calculate the distance by the ball clear the crossbar

Using formula for vertical distance

d=h-3.05

Put the value of h

d=4.2-3.05

d=1.15\ m

Hence, The distance by the ball clear the crossbar is 1.15 m

7 0
3 years ago
A 4kg and 5kg bodies moving on a frictionless horizontal surface at a velocity of ( -6i )m/s and ( +3 )m/s respectively. Collide
Vladimir [108]

Answer:

4 kg → +4 m/s

5 kg → -5 m/s

Explanation:

The law of conservation of momentum states that:

  • m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
  • left side → velocities before collision
  • right side → velocities after collision

You'll notice that we have two missing variables: v₁' & v₂'. Assuming this is a perfectly elastic collision, we can use the conservation of kinetic energy to set the initial and final velocities of the individual bodies equal to each other.

  • v₁ + v₁' = v₂ + v₂'  

Let's substitute all known variables into the first equation.

  • (4)(-6) + (5)(3) = (4)v₁' + (5)v₂'
  • -24 + 15 = 4v₁' + 5v₂'
  • -9 = 4v₁' + 5v₂'  

Let's substitute the known variables into the second equation.

  • (-6) + v₁' = (3) + v₂'
  • -9 = -v₁' + v₂'
  • 9 = v₁' - v₂'  

Now we have a system of equations where we can solve for v₁ and v₂.

  • -9 = 4v₁' + 5v₂'
  • 9 = v₁' - v₂'  

Use the elimination method and multiply the bottom equation by -4.

  • -9 = 4v₁' + 5v₂'
  • -36 = -4v₁' + 4v₂'

Add the equations together.

  • -45 = 9v₂'
  • -5 = v₂'

<u>The final velocity of the second body (5 kg) is -5 m/s</u>. Substitute this value into one of the equations in the system to find v₁.  

  • 9 = v₁' - v₂'
  • 9 = v₁' - (-5)
  • 9 = v₁' + 5
  • 4 = v₁'

<u>The final velocity of the first body (4 kg) is 4 m/s.</u>

<u></u>

We can verify our answer by making sure that the law of conservation of momentum is followed.

  • m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
  • (4)(-6) + (5)(3) = (4)(4) + (5)(-5)
  • -24 + 15 = 16 - 25
  • -9 = -9

The combined momentum of the bodies before the collision is equal to the combined momentum of the bodies after the collision. [✓]

3 0
2 years ago
A projectile is fired from a gun near the surface of earth. the initial velocity of the projectile has a vertical component of 9
nadezda [96]
The gravitational acceleration experienced by the bullet due to the earth's gravitational force is approximately equals to 9.81 m/s^2

At maximum point of height, vertical component of velocity equals to zero because it experiences a pause momentarily before coming back down.

Since -acceleration=(Final velocity-initial velocity) divided by time. Taking upwards to be positive, time taken= 10s
8 0
3 years ago
Read 2 more answers
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