For the first one we divide every element by sqrt3
we get
q+2/sqrt3 =sqrt5/sqrt3
q=(sqrt5-2)/sqrt3
q=sqrt3*sqrt5-2*sqrt3/3
q=sqrt15-2sqrt3/3
which is the third option
For the second one
sqrt(2y-5) +4=8
first we move the 4 to the right
sqrt(2y-5)=4
we remove the square root by bringing to the power of two
2y-5=16
2y=21
y=21/2
y=10 1/2
third option
Answer:
AC ≈ 9,7sm
Step-by-step explanation:
AB=7 One side of a right triangle
BC=12 Hypotenuse of a right triangle
AC=?=x The other side of a right triangle
x²+7²=12²
x²=144-49
x²=95
x=√(95) ≈ 9,7
Answer:43%
just finished test
