Answer:
115
Step-by-step explanation:
5\color{red}{x}+\color{blue}{168}=
5x+168=
\,\,\color{purple}{743}
743
-\color{blue}{168}\phantom{=}
−168=
\,\,-\color{blue}{168}
−168
Subtract 168 from both sides
5\color{red}{x}=
5x=
\,\,575
575
\frac{5\color{red}{x}}{5}=
5
5x
=
\,\,\frac{575}{5}
5
575
Divide both sides by 5
\color{red}{x}=
x=
\,\,\boxed{\color{red}{115}}
115
Answer:
![g(x)=\sqrt[3]{x}-5](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-5)
Step-by-step explanation:
Consider the given function is
![f(x)=\sqrt[3]{-2x+4}-5](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B-2x%2B4%7D-5)
It is given that 
and neither g(x) nor h(x) is solely x.
![f(x)=\sqrt[3]{(-2x+4)}-5](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B%28-2x%2B4%29%7D-5)
Let , then we get
![f(x)=g(h(x))=\sqrt[3]{h(x)}-5](https://tex.z-dn.net/?f=f%28x%29%3Dg%28h%28x%29%29%3D%5Csqrt%5B3%5D%7Bh%28x%29%7D-5)
Substitute h(x)=x in the above function.
Therefore, the required functions are and .
Check the solutions.
![[\because h(x)=-2x+4]](https://tex.z-dn.net/?f=%5B%5Cbecause%20h%28x%29%3D-2x%2B4%5D)
![g(h(x))=\sqrt[3]{-2x+4}-5](https://tex.z-dn.net/?f=g%28h%28x%29%29%3D%5Csqrt%5B3%5D%7B-2x%2B4%7D-5)
![[\because g(x)=\sqrt[3]{x}-5]](https://tex.z-dn.net/?f=%5B%5Cbecause%20g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-5%5D)
Therefore, our solution is correct.
Answer:
i think it would be B
Step-by-step explanation:
Well you see 0.35 would be larger because u need to add 0 to 0.35 cause there isnt a thousandth place for it and 0.062 has thousandth place which is the 2 so ya thats the difference 0.35 is larger than 0.062 and 0.35 doesnt have a thousandth place like 0.062 it has thousandth place which i told u is 2
