Question

Willing to give out Brainliest: 3.00 m^3 of water is at 20.0°C If you raise its temperature to 60.0°C, by how much will its volume expand ?

Answer 1

Answer:

0.02484

Explanation:

Trust me bro

Answer 2

Answer:

The answer is below

Explanation:

Charlee's law states that the volume of a gas is directly proportion to the temperature of the gas at constant pressure. That is:

V = kT, where V = volume and T = temperature, k = constant. Therefore:

V / T = k

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Given that: $V_1=3\ m^3, T_1=20^oC=(20 + 273)K=293\ k,T_2=60^oC=(60 + 273)K=333\ k.\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{3}{293}=\frac{V_2}{333} \\\\V_2=\frac{3}{293}*333\\\\V_2=3.41\ m^3$

The new volume is 3.41 m³. That is it expands by 0.41 m³