Question

Two 100kg bumper cars are moving towards eachother in oppisite directions. Car A is moving at 8 m/s and Car B at -10 m/s when they collide head on. If the resulting velocity of Car B after the collision is 8 m/s, what is the velocity of Car A after the collision

Answer 1

Answer:

$-10 m/s$

Explanation:

When two cars collide then the momentum of two cars will remains conserved

• Mass of two cars = 100 kg

• Speed of car A = 8 m/s

• Speed of car B = - 10 m/s

• After collision the speed of car B = +8 m/s

By momentum conservation equation

               $m1v1i+m2v2i=m1v1f + m2v2f$

               $(100)(8)+(100)(-10)=(100v)+(100)(8)\\ v=-10 m/s$