7. A loaded tractor-trailer with a total mass of 5000 kg traveling at hits a loading dock and comes to a stop in 0.64 s. What is
1 answer:
Complete Question
A loaded tractor-trailer with a total mass of 5000 kg traveling at 3.0 km/h hits a loading dock and comes to a stop in 0.64 s. What is the magnitude of the average force exerted on the truck by the dock
Answer:
The value is
Explanation:
From the question we are told that
The total mass is
The time taken to come to a stop is
The initial velocity is
Generally the magnitude of the average force exerted on the truck by the dock is mathematically represented as
Here v is the final velocity which is zero since the truck came to a stop
=>
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Answer:
a) 1.89 m/s b) 172.1 N
Explanation:
a)
- Applying the work-energy theorem, if we can neglect the friction between truck and road, the total change in kinetic energy must be equal to the work done by the external forces.
- This work, is just 4,475 J.
- So we can write the following equation:
- where m= mass of the truck = 2.5*10³ kg.
- So, we can find the speed v, as follows:
b)
- The work done by the man, is just the horizontal force applied, times the displacement produced by the force horizontally:
- We can solve for F, as follows: