Complete Question
A loaded tractor-trailer with a total mass of 5000 kg traveling at 3.0 km/h hits a loading dock and comes to a stop in 0.64 s. What is the magnitude of the average force exerted on the truck by the dock
Answer:
The value is
Explanation:
From the question we are told that
The total mass is
The time taken to come to a stop is
The initial velocity is
Generally the magnitude of the average force exerted on the truck by the dock is mathematically represented as
Here v is the final velocity which is zero since the truck came to a stop
=>
Answer:
V= 33.98 m/s
Explanation:
Given that
Horizontal speed ,u= 17 m/s
Time taken by rockets to strike the water ,t= 3 s
We know that acceleration due to gravity ,g= 9.81 m/s²
There is no any acceleration in the horizontal direction that is why the horizontal veloity will remain constant.
In the vertical direction
vy = uy+ g t
Initial velocity in vertical direction is 0 m/s.
vy= 0+ 9.81 x 3
vy = 29.43 m/s
The resultant velocity
V= 33.98 m/s
Sasha is correct: No, the velocity is changing at the top so the acceleration cant be zero.
Explanation:
The acceleration of an object is equal to the rate of change in velocity of the object:
(1)
where
is the change in velocity
is the time interval
For the cart on the ramp, as the cart reaches the top of the ramp, its velocity becomes temporarily zero:
v = 0
This is the origin of Malia's mistake.
However, this only lasts a moment; in reality, its velocity is changing, in particular its direction is changing (from upward to downward).
As we can see from eq.(1), a non-zero change in velocity implies a non-zero acceleration. Therefore, Sasha is right, since the cart has a non-zero acceleration.
Learn more about acceleration:
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