Question

7. A loaded tractor-trailer with a total mass of 5000 kg traveling at hits a loading dock and comes to a stop in 0.64 s. What is the magnitude of the average force exerted on the truck by the dock

Answer 1

Complete Question

A loaded tractor-trailer with a total mass of 5000 kg traveling at  3.0 km/h hits a loading dock and comes to a stop in 0.64 s. What is the magnitude of the average force exerted on the truck by the dock

Answer:

The value is  $F = 6508 \ N$

Explanation:

From the question we are told that

  The total mass is  $M_t = 5000 \ kg$

  The time taken to come to a stop is $t = 0.64 \ s$

   The initial velocity is $u = 3.0 km/h = 0.833 \ m/s$

Generally the magnitude of the average force exerted on the truck by the dock is mathematically represented as

        $F = \frac{mu - mv}{t}$

Here v is the final velocity which is zero since the truck came to a stop

      $F = \frac{5000* 0.833 - 5000 * 0}{0.64 }$

=>    $F = 6508 \ N$