7. A loaded tractor-trailer with a total mass of 5000 kg traveling at hits a loading dock and comes to a stop in 0.64 s. What is
1 answer:
Complete Question
A loaded tractor-trailer with a total mass of 5000 kg traveling at 3.0 km/h hits a loading dock and comes to a stop in 0.64 s. What is the magnitude of the average force exerted on the truck by the dock
Answer:
The value is
Explanation:
From the question we are told that
The total mass is
The time taken to come to a stop is
The initial velocity is
Generally the magnitude of the average force exerted on the truck by the dock is mathematically represented as
Here v is the final velocity which is zero since the truck came to a stop
=>
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Answer:
ΔK = 24 joules.
Explanation:
Δ Work done on the object
Work is equal to the dot product of force supplied and the displacement of the object.
* Δ
Δ can be found by subtracting the vectors (7.0, -8.0) and (11.0, -5.0), which is written as Δ
= (11.0 - 7.0, -5.0 - -8.0) which equals (4.0, 3.0).
This gives us
*
=
=
J