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Furkat [3]
3 years ago
5

Explain why a magnetic material is attracted by a magnet.​

Physics
1 answer:
natita [175]3 years ago
7 0

Answer:

Magnetic materials are naturally attracted to other magnets

Explanation:

I hope I got this right

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A wave has a wavelength of 20 mm and a frequency of 5 Hz what is the speed?
yKpoI14uk [10]
The answer is 100mm/s. I hope this helps :)

7 0
3 years ago
What are the factors of works?
olga2289 [7]

Answer:

Explanation:

The seven factors are work load, family life, transportation, compensation policy and benefits, colleagues and supervisor, working environment and working condition and career growth.

4 0
3 years ago
Suppose that a steel bridge, 1000 m long, were built without any expansion joints. Suppose that only one end of the bridge was h
Stels [109]

Answer:

The difference in the length of the bridge is 0.42 m.

Explanation:

Given that,

Length = 1000 m

Winter temperature = 0°C

Summer temperature = 40°C

Coefficient of thermal expansion \alpha= 10.5\times10^{-6}\ K^{-1}

We need to calculate the difference in the length of the bridge

Using formula of the difference in the length

\Delta L=L\alpha\Delta T

Where, \Delta T= temperature difference

\alpha=Coefficient of thermal expansion

L= length

Put the value into the formula

\Delta L=1000\times10.5\times10^{-6}(40^{\circ}-0^{\circ})

\Delta L=0.42\ m

Hence, The difference in the length of the bridge is 0.42 m.

5 0
3 years ago
A 2.00 kg box slides on a rough, horizontal surface, hits a spring with a speed of 1.90 m/s and compresses it a distance of 10.0
oksian1 [2.3K]

Answer:

Explanation:

Given

mass of box m=2\ kg

speed of box v=1.9\ m/s

distance moved by the box x=10\ cm

coefficient of kinetic friction \mu _k=0.66

Friction  force f_r=\mu_kN

f_r=0.66\times mg

f_r=0.66\times 2\times 9.8=12.936 \N

Kinetic Energy of box will be utilize to overcome friction and rest is stored in spring in the form of elastic potential energy

\frac{1}{2}mv^2=f_r\cdot x+\frac{1}{2}kx^2

\frac{1}{2}\times 2\times 1.9^2=12.936\times 0.1+\frac{1}{2}\times k\times (0.1)^2

3.61-1.2936=0.005\times k

k=463.28\ N/m

3 0
3 years ago
Read 2 more answers
A 25kg chair initially at rest on a horizontal floor requires a 165 N horizontal force to set it in motion. Once the chair is in
SCORPION-xisa [38]

Answer:

\mu_k=0.51  

Explanation:

Given that

Mass , m = 25 kg

We know that when body is in rest condition then static friction force act on the body and when body is in motion the kinetic friction force act on the body .That is why these two forces are given as follows

Static friction force ,fs= 165 N

Kinetic friction force ,fk = 127 N

If the body is moving with constant velocity ,it means that acceleration of that body is zero and all the forces are balanced.

Lets take coefficient of kinetic friction  = μk

The kinetic friction is given as follows

fk = μk  m g

Now by putting the values

127 = μk x 25 x 9.81

\mu_k=\dfrac{127}{25\times 9.81}

\mu_k=0.51

Therefore the value of coefficient of kinetic friction will be 0.51

4 0
3 years ago
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