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navik [9.2K]
3 years ago
6

Review 1: A plane is located x = 40 miles (horizontally) away from an airport at an altitude of h miles. Radar at the airport de

tects that the distance s(t) between the plane and airport is changing at the rate of s(t) = −240 mph. If the plane flies toward the airport at the constant altitude h = 4, what is the speed |x(t)| of the airplane?
Physics
1 answer:
-Dominant- [34]3 years ago
8 0

Explanation:

Let h is the height of the plane above ground. x is the horizontal distance between the ground and the airport. Let s(t) is the distance between the plane and the airport. So,

s(t)^2={h^2+x^2}...........(1)

Given, h = 4, x = 40 and s(t) = -20 mph

Differentiate equation (1) wrt t

2s(t)s'(t)=2x(t)x'(t)

x'(t)=\dfrac{s(t)s'(t)}{x(t)}

When x = 40, s(t)=\sqrt{40^2+4^2}=40.19\ m

x'(t)=\dfrac{-240s(t)}{x(t)}

x'(t)=\dfrac{-240\times 40.19}{40}

x'(t)=-241.14\ m/s

So, the speed of the airplane is 241.14  m/s. Hence, this is the required solution.

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