1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
evablogger [386]
2 years ago
6

ZABC and ZQRS are supplementary angles.

Mathematics
2 answers:
Elenna [48]2 years ago
5 0

THEOREM:

  • Supplementary angle —: Two angles are called supplementary when their measures add up to 180 degrees.

ANSWER:

By supplementary angle theorem,

  • m∠ABC + m∠QRS = 180°
  • 100° + m∠QRS = 180°
  • m∠QRS = 180° – 100°
  • m∠QRS = 80°

Hence, the measure of m∠QRS is 80°.

Anastasy [175]2 years ago
4 0

Answer:

dum b

Step-by-step explanation:

You might be interested in
A car travels 294 miles on a full tank of gas. The car's gas tank holds 14 gallons. How many yards per gallon can this car trave
sattari [20]
294 / 14 = 21 miles per gallon
21 * (5280 ft per mile / 3 yards per foot) =
36,960 yards per gallon

4 0
3 years ago
Significant figures in a measurement include all of the digits that are
bonufazy [111]
If you were to make your own measurements, your significant digits should include all of the measurable digits (the digits that correspond to the marks on the ruler) as well as one estimated position beyond the smallest measureable digit (the 5 in 3.5 cm, and the 2 in 3.52 cm).
5 0
3 years ago
A plane flew 360km in 3 hrs when flying with the wind.With no change in the wind,the return trip took 4 hrs.Find the speed of th
morpeh [17]
Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.
6 0
2 years ago
Identify which triangles are congruent, and explain your answer.
Paha777 [63]
I believe that A and D would be the correct answer. Because both are 30,60,90 triangles and would be congruent. The other 2 triangles only have 1 angle and their side measures are at two different places meaning they cannot be congruent.
7 0
3 years ago
Read 2 more answers
Need help have pictures I will mark you the brainiest
morpeh [17]

Answer: If m<aob the x=2

4 0
3 years ago
Other questions:
  • Evalute 16^1/2×2^-3.
    12·1 answer
  • Your computer supply store sells two types of laser printers. The first type, A, has a cost of $86 and you mame a $45 profit on
    11·2 answers
  • Patty is 3 times as old as her brother, Terry. In 10 years, the sum of their ages will be 36. How old are they now?
    10·1 answer
  • Question in pic, will mark brainliest
    11·2 answers
  • Simplify the following expression.<br> X^-2/3 multiplied by x^6/7
    7·1 answer
  • Whats the solution to 4(0.8x+2.5)&lt;2(0.125x-0.9)
    15·1 answer
  • PLZ IN NEED OF HELP!
    8·1 answer
  • An underwater telephone cable is to cross a shallow lake from point A to point B. Stakes are located at
    15·1 answer
  • . <br> Please help<br> Add or subtract.
    15·2 answers
  • Write an equation of a line that passes through (0 -5) and (2, -5)
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!