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Svetllana [295]
2 years ago
5

Two microphones are connected to a

Physics
1 answer:
ale4655 [162]2 years ago
5 0

Answer:

344.8 m/s

Explanation:

Looking for speed of sound  = meters / sec

       2 meters / .0058 seconds = 344.8 m/s

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Why do we need to have an understanding about impulse and momentum ?
bonufazy [111]
Impulse is the interval of a force ,f,over the time interval ,t,for which it acts
Formula p=f t
Momentum is the quantity of motion of a moving body measured as a product of its mass and velocity
Formula p=m v
P=momentum
M=mass
V=velocity
8 0
3 years ago
In which type of circuit does a charge have only one loop to flow through
worty [1.4K]
That would be a series circuit
5 0
4 years ago
A mass is bobbing up and down on a spring. If you increase the amplitude of the motion, how does this affect the time for one os
NikAS [45]

Answer:

It will not change

Explanation:

The period of oscillation of a mass-spring system is given by

T=2\pi \sqrt{\frac{m}{k}}

where

T is the period

m is the mass hanging on the spring

k is the spring constant

As we see from the formula, the period of oscillation does not depend on the amplitude of the motion: therefore, if we change the amplitude, the time for one oscillation will not change.

6 0
3 years ago
3. Which of the following is an example of Newtons second law of motion? (2 points)
Crank

Answer:b

Explanation: i took the test and b was correct

4 0
3 years ago
An object of mass M oscillates on the end of a spring. To double the period, replace the object with one of mass: (a) 2M. (b)M/2
harkovskaia [24]

Answer:

(c) 4M

Explanation:

The system is a loaded spring. The period of a loaded spring is given by

T = 2\pi\sqrt{\dfrac{m}{k}}

<em>m</em> is the mass and <em>k</em> is the spring constant.

It follows that, since <em>k</em> is constant,

T\propto\sqrt{m}

\dfrac{T}{\sqrt{m}} = C where <em>C</em>  represents a constant.

\dfrac{T_1}{\sqrt{m_1}} = \dfrac{T_2}{\sqrt{m_2}}

m_2 = m_1\left(\dfrac{T_2}{T_1}\right)^2

When the period is doubled, T_2 = 2T_1.

m_2 = m_1\left(\dfrac{2T_1}{T_1}\right)^2 = 4m_1

Hence, the mass is replaced by 4M.

7 0
4 years ago
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