The equator would be warmer than the poles. :)
Answer:
v = 4374 Km/h
Explanation:
Given that,
Mass of the smaller object, m = 2 Kg
Mass of the bigger object, M = 1500 Kg
Velocity of the bigger object, V = 1.62 m/s
Velocity of the smaller object, v = ?
The product of its mass and velocity of a body is equal to its linear momentum. It is given by the formula
p = mv Kg m/s
To find the momentum of the bigger object, substitute M and V in the above equation
p = 1500 Kg x 1.62 m/s
= 2430 Kg m/s
The velocity imparted to the small body to attain this momentum is given by the relation
v = p/m m/s
= 2430 Kg m/s / 2 Kg
= 1215 m/s
By converting the velocity to Km/h
v = 4374 km/h
Hence, the velocity of the 2 Kg object is v = 4374 km/h
No, if the car were moving sideways, then the forces used would be on the horizontal axis. So the weight equation would be extraneous, unless one is determining the net force through an inclined plane
Answer:
27.22 F.
Explanation:
T ( t ) = T₀ + ( T₁ - T₀)
T ( t ) = 41 , T₀ = 0 , T₁ = 140 , t = 15
Put these values in the equation above
41 = ( 140 - 0 ) e^{-15k}
41/140 = e ^{-15k}
(41/140)^{1/3} = e ^{-5k}
Let after 20 minutes temperature becomes T
T = 0 + 140 e^{-k20}
T / 41 = e^{-5k }
= (41/140)^{1/3}
T = 41 X (41/140)^{1/3}
= 27.22 F.
Answer:
D. Histogram.
Explanation:
A histogram with equal intervals is suitable here.
