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fomenos
3 years ago
7

PLEASE HELP ME! I AM COFUZZED!

Mathematics
1 answer:
Artemon [7]3 years ago
8 0

so at 8AM the temperature was less than -7C, so recall that on the negative side, the farther from 0, the smaller, so that number could be say -8C, or -9C or -10C or even say -20C, all those are lesser than -7C, and therefore colder as well.

let's say it was -20C, by noon it went up by 7C, so it became -20 + 7 = -13, well, -13C is still less than -7C, so that'd be true for the B) statement.

let's say it was -10C, by noon it went up by 7C, so it became -10 + 7 = -3, well, -3 is more than -7 and less than 0, so that'd be true for the D) statement.

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The area of a circle with the radius 3 feet is ____ ft^2 ? Rounded to the nearest hundredths
nordsb [41]

Answer:

28.26ft^2

Step-by-step explanation:

The formula for area of circle is:

A=3,14*r^2, where r =3 and 3,14 is pie number, so we have

A=3.14*9=28,26

5 0
3 years ago
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Write the square of the binomial as a polynomial: (-1 1/3p + 6q)^2
Thepotemich [5.8K]

Answer:

\frac{16}{9}p² -16pq + 36q²

Step-by-step explanation:

Given

(- \frac{4}{3}p + 6q)²

= (- \frac{4}{3}p + 6q)(- \frac{4}{3}p + 6q)

Each term in the second factor is multiplied by each term in the first factor, that is

- \frac{4}{3}p(- \frac{4}{3}p + 6q) + 6q(- \frac{4}{3}p + 6q)

= \frac{16}{9}p² - 8pq - 8pq + 36q² ← collect like terms

= \frac{16}{9}p² - 16pq + 36q²

5 0
4 years ago
Which of the statements below is true for the following set of numbers?
Taya2010 [7]

Answer:

The range is 40 and the midrange is 20.

4 0
3 years ago
Question<br> What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
vlada-n [284]

The value of x is 4/3

What are trigonometric relations?

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

tan θ = sin θ / cos θ

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

Given data ,

Let the triangles be ΔRST and ΔQRT

Now , from the figure

∠S = 90° in the triangle ΔRST

And RS = 2/√3

∠T = 60° in the triangle ΔRST

Now ,

sin 60° = opposite / hypotenuse

           = RS / RT

           = ( 2/√3 ) / RT

We know , sin 60° = √3 / 2

Substituting the value of  sin 60° in the equation , we get

√3 / 2 = ( 2 / √3 ) / RT

Multiply by RT on both sides , we get

RT x ( √3 / 2  ) =  ( 2 / √3 )

Divide by ( √3 / 2  ) on both sides , we get

RT = ( 2 / √3 ) x ( 2 / √3 )

RT = 4 / 3

Therefore , the value of RT = 4/3

Now , from the figure

∠R = 90° in the triangle ΔQRT

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So ,

tan 45° = opposite / adjacent

We know tan 45° = 1

Substituting the value for tan 45° = 1 in the equation , we get

1 = opposite / adjacent

1 = x / RT

Multiply by RT on both sides , we get

x = RT

So , x = 4/3

Hence , The value of x is 4/3

To learn more about trigonometric equations click :

brainly.com/question/14746686

#SPJ1

5 0
1 year ago
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Verizon [17]

Answer:

The answer is c

Step-by-step explanation:

Well, since the Circle is 8cm you can divide the circle by two to get 4

5 0
3 years ago
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