Answer:
<h2>
<em>1</em><em>5</em><em> </em><em>units</em></h2>
<em>The </em><em>length </em><em>of </em><em>BC </em><em>is </em><em>1</em><em>5</em><em> </em><em>units.</em>
<em>Solution,</em>
<em>Hypotenuse(</em><em>h)</em><em>=</em><em>?</em>
<em>perpendicular(</em><em>p)</em><em>=</em><em>1</em><em>2</em>
<em>base(</em><em>b)</em><em>=</em><em>9</em>
<em>Using </em><em>Pythagoras</em><em> </em><em>theorem</em><em>,</em>
<em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
X^3 + x^2 + x
Step-by-step explanation:
First, distribute the negative sign to the numbers in the second parentheses. Then you’ll need to combine like terms.
The answer is 6t^2+2.5x^2-0.5t-5.4
Answer:
The probability that he chooses trees of two different types is 30%.
Step-by-step explanation:
Given that a landscaper is selecting two trees to plant, and he has five to choose from, of which three of the five are deciduous and two are evergreen, to determine what is the probability that he chooses trees of two different types must be performed the following calculation:
3/5 x 2/4 = 0.3
2/5 x 3/4 = 0.3
Therefore, the probability that he chooses trees of two different types is 30%.
Answer:
FG
Step-by-step explanation:
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