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Debora [2.8K]
2 years ago
12

Sonya had 20 dollars to spend on 3 gifts. She spent 8 1 4 dollars on gift A and 4 4 5 dollars on gift B. How much money did she

have left for gift C?
Mathematics
1 answer:
Natasha2012 [34]2 years ago
6 0

Answer:

6 19/20 dollars

Step-by-step explanation:

Sonya had 20 dollars to spend on 3 gifts.

She spent 8 1 4 dollars on gift A and 4 4 5 dollars on gift B.

Gift A + Gift B + Gift C = $20

Gift C = $20 - (Gift A + Gift B)

Gift A = $8 1/4

Gift B = $4 4/5

Hence:

The amount she had left for gift C is :

Gift C = $20 - ($8 1/4 + $ 4 4/5)

Gift C = $20 - $13 1/20

Gift C = $ 6 19/20

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Omar grouped the terms and factored the GCF out of the groups of the polynomial 3x3 – 15x2 – 4x + 20. His work is shown.
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Answer:

2nd option

Step-by-step explanation:

Given

3x³ - 15x² - 4x + 20

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(3x³ - 15x² ) + (- 4x + 20)

step  2 ( factor each group )

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Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
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<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
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<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

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\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

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Octahedron (8) is a <span>polyhedron has more faces than a hexahedron, but fewer faces than an dodecahedron.</span>

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