The third reaction will form a gaseous product, CO₂
KHCO₃ + HBr → KBr + H₂O + CO₂
Answer:
The nuclear fuel used in a nuclear reactor needs to have a higher concentration of the U 235 isotope than that which exists in natural uranium ore. U235 when concentrated (or "enriched") is fissionable in light-water reactors (the most common reactor design in the USA).
Explanation:
Answer:
=<em><u> 0.42 moles of CO2 </u></em>
Explanation:
From Avogadro's constant
6.02×10^23 molecules are in 1 mole of CO2
2.54×10^23 molecules will be in
=[(2.54×10^23) ÷ (6.02×10^23)]
= 0.42 moles of CO2
Answer: This can be quickly solved with "traintracks"
Explanation:
You start w/ grams of water and want to find moles of oxygen gas produced.
So you want to Convert:
Grams of water -> moles of water -> moles of oxygen gas.
The two things you need to know to set up the tracks are:
1)Molar mass of water- H2O
Hydrogen - 1.008(x2)
Oxygen - 16.00
Water - 18.016
