Answer:
12.99
Explanation:
<em>A chemist dissolves 716. mg of pure potassium hydroxide in enough water to make up 130. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits.</em>
Step 1: Given data
- Mass of KOH: 716. mg (0.716 g)
- Volume of the solution: 130. mL (0.130 L)
Step 2: Calculate the moles corresponding to 0.716 g of KOH
The molar mass of KOH is 56.11 g/mol.
0.716 g × 1 mol/56.11 g = 0.0128 mol
Step 3: Calculate the molar concentration of KOH
[KOH] = 0.0128 mol/0.130 L = 0.0985 M
Step 4: Write the ionization reaction of KOH
KOH(aq) ⇒ K⁺(aq) + OH⁻(aq)
The molar ratio of KOH to OH⁻is 1:1. Then, [OH⁻] = 0.0985 M
Step 5: Calculate the pOH
We will use the following expression.
pOH = -log [OH⁻] = -log 0.0985 = 1.01
Step 6: Calculate the pH
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 -1.01 = 12.99
Density is a physical property. It's measured and doesn't change the object chemically.
Answer:
Aluminium metal reacts vigorously with all the halogens to form aluminium halides. So it reacts with chlorine, bromine, and iodine.
Answer:
- <em>The kinetic energy in J of an electron moving at 6.00 × 10⁻⁶ m/s is:</em>
<em> </em><u>1.64 × 10 ⁻³⁸ J</u>
<em />
Explanation:
<u>1) Data:</u>
a) KE =?
b) v = 6.00 × 10⁻⁶ m/s.
c) m = 9.11 × 10⁻²⁸ g.
<u>2) Formula:</u>
<u>3) Solution:</u>
- KE = (1/2) = (1/2) × 9.11 × 10⁻²⁸ g × ( 6.00 × 10⁻⁶ m/s)² = 163.98 × 10 ⁻⁴⁰ J
