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Marianna [84]
3 years ago
13

Which of the following statements about Earth's inner core is true?

Chemistry
2 answers:
Solnce55 [7]3 years ago
5 0

Answer:

comment the statements and we will help <3

have a great day

Explanation:

zavuch27 [327]3 years ago
4 0
I don’t see anything. So sorry
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Scientists believe that ancient bacteria represents the first evidence of life on Earth. Which of these best describes the proce
Goryan [66]
I would probably say transformation of virus like molecules
3 0
3 years ago
How many atoms, ions, or molecules are in a 1 molar solution?
Nezavi [6.7K]

Molarity refers to moles/ L. This indicates the concentration of a solution containing solute and solvent.

1 molar solution contains 1 mole of solute in 1 L of solvent.

According to Avogadro's number, 1 mole of a substance contains 6.023 x 10^23 molecules, atoms, or ions.

For this reason, 6.023 x 10^23 atoms, ions, or molecules are in a molar solution.

7 0
3 years ago
The diameter of a biscuit is approximately 51 millimeters (mm). An atom of bismuth (Bi) is approximately 320. picometers (pm) in
astraxan [27]

Answer:

1.5e+8 atoms of Bismuth.

Explanation:

We need to calculate the <em>ratio</em> of the diameter of a biscuit respect to the diameter of the atom of bismuth (Bi):

\\ \frac{diameter\;biscuit}{diameter\;atom(Bi)}

For this, it is necessary to know the values in meters for any of these diameters:

\\ 1m = 10^{3}mm = 1e+3mm

\\ 1m = 10^{12}pm = 1e+12pm

Having all this information, we can proceed to calculate the diameters for the biscuit and the atom in meters.

<h3>Diameter of an atom of Bismuth(Bi) in meters</h3>

1 atom of Bismuth = 320pm in diameter.

\\ 320pm*\frac{1m}{10^{12}pm} = 3.20*10^{-10}m

<h3>Diameter of a biscuit in meters</h3>

\\ 51mm*\frac{1}{10^{3}mm} = 51*10^{-3}m = 5.1*10^{-2}m

<h3>Resulting Ratio</h3>

How many times is the diameter of an atom of Bismuth contained in the diameter of the biscuit? The answer is the ratio described above, that is, the ratio of the diameter of the biscuit respect to the diameter of the atom of Bismuth:

\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1*10^{-2}m}{3.20*10^{-10}m}

\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1}{3.20}\frac{10^{-2}}{10^{-10}}\frac{m}{m}

\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1}{3.20}\frac{10^{-2}}{10^{-10}}\frac{m}{m}

\\ Ratio_{\frac{biscuit}{atom}}= 1.5*10^{-2+10}

\\ Ratio_{\frac{biscuit}{atom}}= 1.5*10^{8}=1.5e+8

In other words, there are 1.5e+8 diameters of atoms of Bismuth in the diameter of the biscuit in question or simply, it is needed to put 1.5e+8 atoms of Bismuth to span the diameter of a biscuit in a line.

6 0
3 years ago
Which statement is true about BF3, a nonpolar molecule? It has nonpolar bonds and a symmetrical structure. It has nonpolar bonds
konstantin123 [22]
I think the correct answer is the first option. It has nonpolar bonds and a symmetrical structure. The structure of a BF3 molecule shows a symmetrical trigonal geometry. The net dipole moment of the molecule is zero therefore it is polar.
6 0
3 years ago
Read 2 more answers
1 question content area what is the total number of valence electrons in the lewis structure of sebr2o?
joja [24]

There are 24 valance electrons in the compound.

<h3>What are valence electrons?</h3>

We know that the valence electrons are those that are found on the valence shell of an atom. There are four atoms that can be seen in the compound that is under consideration. The atoms are selenium, bromine (2 atoms) and oxygen.

Given that there are seven valence electrons in bromine and six valence electrons in oxygen and selenium. We have;

2(7 electrons of bromine) + 6 electrons of oxygen + 4 electrons of Se

= 24 electrons

Learn more about valence electrons:brainly.com/question/8906371

#SPJ1

6 0
1 year ago
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