Question

Ionic equation for Sr3(PO4)2 and its solubility product (Ksp)?​

Answer 1

Answer:

$Sr_3(PO_4)_2(s)\rightleftharpoons 3Sr^{+2}(aq)+2(PO_4)^{-3}(aq)$

$Ksp=[Sr^{+2}]^3[(PO_4)^{-3}]^2$

Explanation:

Hello,

In this case, for strontium phosphate, we find an ionic equation for its dissociation as shown below:

$Sr_3(PO_4)_2(s)\rightleftharpoons 3Sr^{+2}(aq)+2(PO_4)^{-3}(aq)$

Next, the solubility product is found by applying the law of mass action, considering that the solid salt is not considered but just the aqueous species due to heterogeneous equilibrium:

$Ksp=[Sr^{+2}]^3[(PO_4)^{-3}]^2$

Best regards.